You can use this class to realize a simple sectioned RecyclerView.Adapter
without changing your code.
The RecyclerView
should use a LinearLayoutManager
.
You can use this code also with the TwoWayView
with the ListLayoutManager
(https://github.com/lucasr/twoway-view)
This is a porting of the class SimpleSectionedListAdapter
provided by Google
Example:
//Your RecyclerView
mRecyclerView = (RecyclerView) findViewById(R.id.list);
mRecyclerView.setHasFixedSize(true);
mRecyclerView.setLayoutManager(new LinearLayoutManager(this));
mRecyclerView.addItemDecoration(new DividerItemDecoration(this,LinearLayoutManager.VERTICAL));
//Your RecyclerView.Adapter
mAdapter = new SimpleAdapter(this,sCheeseStrings);
//This is the code to provide a sectioned list
List<SimpleSectionedRecyclerViewAdapter.Section> sections =
new ArrayList<SimpleSectionedRecyclerViewAdapter.Section>();
//Sections
sections.add(new SimpleSectionedRecyclerViewAdapter.Section(0,"Section 1"));
sections.add(new SimpleSectionedRecyclerViewAdapter.Section(5,"Section 2"));
sections.add(new SimpleSectionedRecyclerViewAdapter.Section(12,"Section 3"));
sections.add(new SimpleSectionedRecyclerViewAdapter.Section(14,"Section 4"));
sections.add(new SimpleSectionedRecyclerViewAdapter.Section(20,"Section 5"));
//Add your adapter to the sectionAdapter
SimpleSectionedRecyclerViewAdapter.Section[] dummy = new SimpleSectionedRecyclerViewAdapter.Section[sections.size()];
SimpleSectionedRecyclerViewAdapter mSectionedAdapter = new
SimpleSectionedRecyclerViewAdapter(this,R.layout.section,R.id.section_text,mAdapter);
mSectionedAdapter.setSections(sections.toArray(dummy));
//Apply this adapter to the RecyclerView
mRecyclerView.setAdapter(mSectionedAdapter);
You can customize the section layout, changing the layout section.xml and changing the code in the SimpleSectionedRecyclerViewAdapter.SectionViewHolder
class and SimpleSectionedRecyclerViewAdapter#onBindViewHolder
method.
Great idea, but maybe you could add a license so that I can be copy it without the risk of a copyright infringement?