Naive Python fizzbuzz with no divide or modulo.

py_fizzbuzz_nodivmod

def fizzbuzz(stop):
     count_3 = count_5 = 0
     for i in range(1, stop + 1):
         count_3 += 1
         count_5 += 1
         if count_3 == 3 and count_5 == 5:
             print('fizzbuzz')
             count_3 = count_5 = 0
         elif count_3 == 3:
             print('fizz')
             count_3 = 0
         elif count_5 == 5:
             print('buzz')
             count_5 = 0
         else:
             print(i)