Created
September 14, 2015 20:38
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O(n) solution to the maximum subarray sum problem using Kadane's algorithm
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#include <tuple> | |
#include <iterator> | |
#include <algorithm> | |
template <class InputIterator> | |
std::tuple<typename std::iterator_traits<InputIterator>::value_type, | |
InputIterator, InputIterator> | |
maximum_subarray(InputIterator first, InputIterator last) { | |
typedef typename std::iterator_traits<InputIterator>::value_type value_type; | |
using std::max; | |
value_type max_ending_here(0), max_so_far(0); | |
InputIterator max_start, max_end; | |
max_start = max_end = first; | |
while (first != last) { | |
if (*first < max_ending_here + *first) | |
max_ending_here += *first; | |
else { | |
max_ending_here = *first; | |
max_start = first; | |
} | |
if (max_so_far < max_ending_here) { | |
max_so_far = max_ending_here; | |
max_end = first + 1; | |
} | |
++first; | |
} | |
return std::make_tuple(max_so_far, max_start, max_end); | |
} |
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