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December 18, 2015 02:19
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| avg xs = sm/lng | |
| where (sm,lng) = foldl avgr (0,0) xs | |
| avgr (s,l) x = (x+s,1+l) |
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| def avg(xs:List[Int]):Float={ | |
| val (sum,length)=xs.foldLeft((0,0))( { case ((s,l),x)=> (x+s,1+l) }) | |
| sum/length | |
| } |
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Average of a list in one pass using tupling (banana split?)