Created
September 18, 2021 00:43
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var kConcatenationMaxSum = function(arr, k) { | |
let maxSum = calculateMaxSubArraySum(arr) | |
if (k === 1) return maxSum | |
let newArr = [...arr, ...arr] | |
let sum = calculateMaxSubArraySum(newArr) | |
if (sum <= maxSum) { | |
return maxSum | |
} | |
maxSum = sum | |
newArr = [...newArr, ...arr] | |
sum = calculateMaxSubArraySum(newArr) | |
if (sum <= maxSum) { | |
return maxSum | |
} | |
return maxSum + (sum - maxSum) * (k - 1) | |
}; | |
function calculateMaxSubArraySum(newArr) { | |
let maxSum = 0 | |
for (let i=0; i < newArr.length; i++) { | |
for (let j=i; j < newArr.length; j++) { | |
let sum = 0 | |
for (let k=i; k <= j; k++) sum += newArr[k] | |
if (sum > maxSum) { | |
maxSum = sum | |
} | |
} | |
} | |
return maxSum; | |
} |
Buenas noches, dejó mi aporte al problema
var kConcatenationMaxSum = function(arr, k) {
let MOD=1000000007
let n=arr.length
const sumMax = (q,n)=>{
let rep=0
let sum=0
let max=0
while(rep<q){
for(let i=0;i<n;i++){
sum+=arr[i]
sum=Math.max(0,sum)
max=Math.max(max,sum)
}
rep++
}
return max
}
if(k===1) return sumMax(k,n)%MOD
else {
let max=sumMax(2,n)
let sumMed=arr.reduce((acc,x)=>acc+x,0)*(k-2)
return Math.max(max,sumMed+max)%MOD
}
};
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Esta solución todavía no funciona. Ayuda!