Created
March 18, 2015 08:03
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Function interpolation using Newton polynomial with Finite Differences
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clear; | |
close all; | |
clc; | |
a = -10; | |
b = 10; | |
n = 14; | |
j = a:0.2:b; | |
h = (b - a)/n; | |
l = a:h:b; | |
syms x; | |
syms c; | |
f = sin(c); | |
y = subs(f, l); | |
P = y(1); | |
fdc(1:size(l, 2), 1:size(l, 2)) = 0; | |
for I=1:1:size(l, 2) | |
for J=1:1:size(l, 2)-1 | |
if I == 1 | |
fdc(J, I) = y(J+1) - y(J); | |
else | |
fdc(J, I) = fdc(J+1, I-1) - fdc(J, I-1); | |
end; | |
end; | |
end; | |
qs = (x - l(1)) / h; | |
Q = qs; | |
for I=2:1:size(l, 2) | |
P = P + fdc(1, I-1) * Q; | |
Q = Q * (qs - I + 1) / I; | |
end; | |
plot(j, subs(f, j), '-b'); | |
hold on; | |
plot(j, subs(P, j), '-r'); | |
title('Num exp, n=7'); | |
legend('f(x)', 'Interpolation'); |
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