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BIN2OCT Function
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// Copyright (c) 2012 Sutoiku, Inc. (MIT License) | |
function BIN2OCT(number, places) { | |
// Return error if number is not binary or contains more than 10 characters (10 digits) | |
if (!/^[01]{1,10}$/.test(number)) return '#NUM!'; | |
// Ignore places and return a 10-character octal number if number is negative | |
var stringified = number.toString(); | |
if (stringified.length === 10 && stringified.substring(0, 1) === '1') { | |
return (1073741312 + parseInt(stringified.substring(1), 2)).toString(8); | |
} | |
// Convert binary number to octal | |
var result = parseInt(number, 2).toString(8); | |
// Return octal number using the minimum number of characters necessary if places is undefined | |
if (typeof places === 'undefined') { | |
return result; | |
} else { | |
// Return error if places is nonnumeric | |
if (isNaN(places)) return '#VALUE!'; | |
// Return error if places is negative | |
if (places < 0) return '#NUM!'; | |
// Truncate places in case it is not an integer | |
places = Math.floor(places); | |
// Pad return value with leading 0s (zeros) if necessary (using Underscore.string) | |
return (places >= result.length) ? _s.repeat('0', places - result.length) + result : '#NUM!'; | |
} | |
} |
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