Created
January 22, 2013 01:45
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IRR Function
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// Copyright (c) 2012 Sutoiku, Inc. (MIT License) | |
// Some algorithms have been ported from Apache OpenOffice: | |
/************************************************************** | |
* | |
* Licensed to the Apache Software Foundation (ASF) under one | |
* or more contributor license agreements. See the NOTICE file | |
* distributed with this work for additional information | |
* regarding copyright ownership. The ASF licenses this file | |
* to you under the Apache License, Version 2.0 (the | |
* "License"); you may not use this file except in compliance | |
* with the License. You may obtain a copy of the License at | |
* | |
* http://www.apache.org/licenses/LICENSE-2.0 | |
* | |
* Unless required by applicable law or agreed to in writing, | |
* software distributed under the License is distributed on an | |
* "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY | |
* KIND, either express or implied. See the License for the | |
* specific language governing permissions and limitations | |
* under the License. | |
* | |
*************************************************************/ | |
function IRR(values, guess) { | |
// Credits: algorithm inspired by Apache OpenOffice | |
// Calculates the resulting amount | |
var irrResult = function(values, dates, rate) { | |
var r = rate + 1; | |
var result = values[0]; | |
for (var i = 1; i < values.length; i++) { | |
result += values[i] / Math.pow(r, (dates[i] - dates[0]) / 365); | |
} | |
return result; | |
} | |
// Calculates the first derivation | |
var irrResultDeriv = function(values, dates, rate) { | |
var r = rate + 1; | |
var result = 0; | |
for (var i = 1; i < values.length; i++) { | |
var frac = (dates[i] - dates[0]) / 365; | |
result -= frac * values[i] / Math.pow(r, frac + 1); | |
} | |
return result; | |
} | |
// Initialize dates and check that values contains at least one positive value and one negative value | |
var dates = []; | |
var positive = false; | |
var negative = false; | |
for (var i = 0; i < values.length; i++) { | |
dates[i] = (i === 0) ? 0 : dates[i - 1] + 365; | |
if (values[i] > 0) positive = true; | |
if (values[i] < 0) negative = true; | |
} | |
// Return error if values does not contain at least one positive value and one negative value | |
if (!positive || !negative) return '#NUM!'; | |
// Initialize guess and resultRate | |
var guess = (typeof guess === 'undefined') ? 0.1 : guess; | |
var resultRate = guess; | |
// Set maximum epsilon for end of iteration | |
var epsMax = 1e-10; | |
// Set maximum number of iterations | |
var iterMax = 50; | |
// Implement Newton's method | |
var newRate, epsRate, resultValue; | |
var iteration = 0; | |
var contLoop = true; | |
do { | |
resultValue = irrResult(values, dates, resultRate); | |
newRate = resultRate - resultValue / irrResultDeriv(values, dates, resultRate); | |
epsRate = Math.abs(newRate - resultRate); | |
resultRate = newRate; | |
contLoop = (epsRate > epsMax) && (Math.abs(resultValue) > epsMax); | |
} while(contLoop && (++iteration < iterMax)); | |
if(contLoop) return '#NUM!'; | |
// Return internal rate of return | |
return resultRate; | |
} |
Thanks you a lot!
This was the most accurate formula I have found
Bro, you're great! 🥇
Thanks, that was perfect
Here's the TypeScript modern version:
// Calculates the resulting amount
const _irrResult = function (values: number[], dates: number[], rate: number) {
const r = rate + 1
let result = values[0]
for (let i = 1; i < values.length; i++) {
result += values[i] / Math.pow(r, (dates[i] - dates[0]) / 365)
}
return result
}
// Calculates the first derivation
const _irrResultDerivation = function (values: number[], dates: number[], rate: number) {
const r = rate + 1
let result = 0
for (let i = 1; i < values.length; i++) {
const frac = (dates[i] - dates[0]) / 365
result -= (frac * values[i]) / Math.pow(r, frac + 1)
}
return result
}
const IRR = (values: number[], guess: number): number => {
// Initialize dates and check values contains at least one positive value and one negative value
const dates = [] as number[]
let positive = false
let negative = false
for (let i = 0; i < values.length; i++) {
dates[i] = i === 0 ? 0 : dates[i - 1] + 365
if (values[i] > 0) positive = true
if (values[i] < 0) negative = true
}
// Return error if values does not contain at least one positive value and one negative value
if (!positive || !negative) {
return NaN
}
// Initialize the guess and the resultRate
let resultRate = typeof guess === 'undefined' ? 0.1 : guess
// Set maximum epsilon for the end of the iteration
const epsMax = 1e-10
// Set maximum count of iterations
const iterMax = 50
// Implement Newton's method
let newRate, epsRate, resultValue
let iteration = 0
let contLoop = true
do {
resultValue = _irrResult(values, dates, resultRate)
newRate = resultRate - resultValue / _irrResultDerivation(values, dates, resultRate)
epsRate = Math.abs(newRate - resultRate)
resultRate = newRate
contLoop = epsRate > epsMax && Math.abs(resultValue) > epsMax
} while (contLoop && ++iteration < iterMax)
if (contLoop) {
return NaN
}
// Return internal rate of return
return resultRate
}
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