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@ghalimi
Created January 30, 2013 01:11
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XIRR Function
// Copyright (c) 2012 Sutoiku, Inc. (MIT License)
// Some algorithms have been ported from Apache OpenOffice:
/**************************************************************
*
* Licensed to the Apache Software Foundation (ASF) under one
* or more contributor license agreements. See the NOTICE file
* distributed with this work for additional information
* regarding copyright ownership. The ASF licenses this file
* to you under the Apache License, Version 2.0 (the
* "License"); you may not use this file except in compliance
* with the License. You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing,
* software distributed under the License is distributed on an
* "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
* KIND, either express or implied. See the License for the
* specific language governing permissions and limitations
* under the License.
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*************************************************************/
function XIRR(values, dates, guess) {
// Credits: algorithm inspired by Apache OpenOffice
// Calculates the resulting amount
var irrResult = function(values, dates, rate) {
var r = rate + 1;
var result = values[0];
for (var i = 1; i < values.length; i++) {
result += values[i] / Math.pow(r, moment(dates[i]).diff(moment(dates[0]), 'days') / 365);
}
return result;
}
// Calculates the first derivation
var irrResultDeriv = function(values, dates, rate) {
var r = rate + 1;
var result = 0;
for (var i = 1; i < values.length; i++) {
var frac = moment(dates[i]).diff(moment(dates[0]), 'days') / 365;
result -= frac * values[i] / Math.pow(r, frac + 1);
}
return result;
}
// Check that values contains at least one positive value and one negative value
var positive = false;
var negative = false;
for (var i = 0; i < values.length; i++) {
if (values[i] > 0) positive = true;
if (values[i] < 0) negative = true;
}
// Return error if values does not contain at least one positive value and one negative value
if (!positive || !negative) return '#NUM!';
// Initialize guess and resultRate
var guess = (typeof guess === 'undefined') ? 0.1 : guess;
var resultRate = guess;
// Set maximum epsilon for end of iteration
var epsMax = 1e-10;
// Set maximum number of iterations
var iterMax = 50;
// Implement Newton's method
var newRate, epsRate, resultValue;
var iteration = 0;
var contLoop = true;
do {
resultValue = irrResult(values, dates, resultRate);
newRate = resultRate - resultValue / irrResultDeriv(values, dates, resultRate);
epsRate = Math.abs(newRate - resultRate);
resultRate = newRate;
contLoop = (epsRate > epsMax) && (Math.abs(resultValue) > epsMax);
} while(contLoop && (++iteration < iterMax));
if(contLoop) return '#NUM!';
// Return internal rate of return
return resultRate;
}
@arikon
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arikon commented May 12, 2022

Found replacement package
https://github.com/eric-malachias/irr

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