Created
July 1, 2018 20:11
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Parallel computation of primes
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#include <stdio.h> | |
#include <math.h> | |
#include <unistd.h> | |
#include <sys/types.h> | |
#define number_of_procs 4 | |
int main() { | |
long i, j, prime, low, high,count_left=0,count_right=0; | |
pid_t p; | |
low = 3; | |
high = 11; | |
long chunck = ceil((high-low)/number_of_procs); | |
long start = low; | |
for (int k=0; k<number_of_procs; k++){ | |
p = fork(); | |
if (p==0){ | |
int end=0; | |
if (start+chunck > high){ | |
end = high; | |
} | |
else{ | |
end = start + chunck; | |
} | |
for (i=start; i<=end; i++){ | |
prime=1; | |
if (i%2==0){ | |
prime=0; | |
} | |
for (j=3; j<(sqrt(i)+1); j+=2){ | |
if ( (i%j) ==0){ | |
prime=0; | |
break; | |
} | |
} | |
if (prime){ | |
printf("%ld is a prime\n",i); | |
} | |
} | |
break; | |
} | |
else { | |
start += chunck + 1; | |
} | |
} | |
} |
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