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September 20, 2019 17:49
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This gist simulates the execution of two async methods using async/await. It returns a message of success when both complete. A random timeout between 1 and 3000ms is being used.
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function randomTimeout() { | |
const t = Math.floor(Math.random() * 3000 + 1); | |
return t; | |
} | |
// SetTimeout does not return a promise, so we can't await for it. This funcion promisify it mannualy. | |
function timeout(ms) { | |
return new Promise(resolve => setTimeout(resolve, ms)); | |
} | |
async function method1() { | |
t = randomTimeout(); | |
await timeout(t); | |
console.log("method1"); | |
} | |
async function method2() { | |
t = randomTimeout(); | |
await timeout(t); | |
console.log("method2"); | |
} | |
Promise.all([method1(), method2()]).then(() => console.log("Success")); |
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