Created
September 15, 2011 16:16
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Looks up how many followers two Twitter accounts do have in common
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#!/usr/bin/env python | |
""" | |
This script looks up how many followers two different Twitter accounts do have in common. | |
Usage: | |
twitter_follower_intersect.py username username | |
You'll need Python and the Python Twitter Tools to get this running. | |
http://pypi.python.org/pypi/twitter/ | |
Also you will have to create an app at https://dev.twitter.com/apps/ | |
and enter your credentials below: | |
""" | |
auth_token = '...' | |
auth_token_secret = '...' | |
consumer_key = '...' | |
consumer_secret = '...' | |
from twitter import Twitter, OAuth | |
import sys, os | |
if len(sys.argv) != 3: | |
print 'Usage:\n\n'+os.path.basename(sys.argv[0])+' screenname1 screenname2'; | |
t = Twitter(auth=OAuth(auth_token, auth_token_secret, consumer_key, consumer_secret)) | |
user_a = sys.argv[1] | |
user_b = sys.argv[2] | |
a = t.followers.ids(user=user_a) | |
b = t.followers.ids(user=user_b) | |
c = [] | |
for id in a: | |
try: | |
b.index(id) | |
c.append(id) | |
except: | |
True | |
print '\n'+user_a, 'has', len(a), 'follower' | |
print user_b, 'has', len(b), 'follower' | |
print user_a, 'and', user_b, 'have', len(c), 'followers in common' | |
if len(c) > 100: | |
c = c[:100] | |
print '\nfirst 100 common followers are:' | |
elif len(c) > 0: | |
print '\nthese are the common followers:' | |
if len(c) > 0: | |
common_info = t.users.lookup(user_id=','.join(map(str, c))) | |
common = [] | |
for u in common_info: | |
common.append(u['screen_name']) | |
print ', '.join(common) | |
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