Created
February 2, 2012 22:01
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Find most valuable followers on Twitter
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from twitter import Twitter, OAuth | |
import json | |
auth_token = 'xxxxxxxxxxxxxx' | |
auth_token_secret = 'xxxxxxxxxxxxxxxx' | |
consumer_key = 'xxxxxxxxxxxxxxxx' | |
consumer_secret = 'xxxxxxxxxxxxxxxx' | |
user = "driven_by_data" | |
t = Twitter(auth=OAuth(auth_token, auth_token_secret, consumer_key, consumer_secret)) | |
def get_follower_ids(user): | |
out = [] | |
cur = -1 | |
while cur != 0: | |
l = t.followers.ids(screen_name=user, cursor=cur) | |
out += l['ids'] | |
cur = l['next_cursor'] | |
return out | |
def get_followers(user): | |
import json | |
follower_ids = get_follower_ids(user) | |
k = len(follower_ids) | |
i = 0 | |
try: | |
cached = json.loads(open('follower_'+user+'.json','r').read()) | |
except: | |
cached = [] | |
if len(cached) == k: | |
followers = cached | |
else: | |
followers = [] | |
while i < k: | |
followers += t.users.lookup(user_id=','.join(map(str, follower_ids[i:i+100]))) | |
i += 100 | |
open('follower_'+user+'.json','w').write(json.dumps(followers)) | |
return followers | |
followers = get_followers(user) | |
followers = sorted(followers, key=lambda user: user['followers_count']*-1) | |
for u in followers[:10]: | |
print u['screen_name'], u['followers_count'] |
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