Created
April 4, 2018 18:21
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Add argument specification to a function call
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argify = function(expr, recursive = FALSE) { | |
if(is.character(expr)) | |
expr = parse(text = expr) | |
else if(!is.call(expr)) | |
expr = substitute(expr) | |
stopifnot(is.call(expr)) | |
if(recursive && length(expr) > 1) { | |
for(i in 2:length(expr)) { | |
if(is.call(expr[[i]])) | |
expr[[i]] = argify(expr[[i]], TRUE) | |
} | |
} | |
fname = as.character(expr[[1]]) #name of function called | |
reffun = get(fname) | |
fun = function() { match.call()} | |
formals(fun) = formals(reffun) | |
assign(fname, fun) | |
eval(expr) | |
} | |
foo = function(arg1, arg2, arg3, arg4) NULL | |
bar = function(bar1, bar2) NULL | |
argify(foo(1, cbind(3, bar(3, 4)), "a", rnorm)) | |
argify(foo(1, cbind(3, bar(3, 4)), "a", rnorm), recursive= TRUE) |
@klmr I think that's right. I had a bunch of balls in the air in terms of what I Was doing with the expression but given where it landed what you said is the better approach for that part.
@HenrikBengtsson you're right, thanks. The need for the [[1]]
slipped my mind there.
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This should use
match.fun
(orget(…, mode = 'function')
);get
alone can fail if the function is shadowed by a (non-function) variable.… but isn’t the function needlessly complicated anyway? The last four lines of the function (L15–L18) can be replaced by a single
No need to inject the call into the original expression.