Created
October 18, 2013 05:58
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https://twitter.com/gongoZ/status/391065716834586624 と問い掛けて「アイテムを大きい順にソートしてもっとも少ないビンに順々に割り当てていく」という案をいただいたので書いてみた
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items = { | |
'hoge' => 1, | |
'fuga' => 2, | |
'hago' => 3, | |
'foo' => 1, | |
'bar' => 8, | |
'baz' => 1, | |
'piyo' => 3, | |
'gongo' => 4, | |
'dududu' => 2 | |
} | |
sorted_items = items.sort { |a, b| b[1] <=> a[1] } | |
boxes = 3.times.map do | |
{ name: [], weight: 0 } | |
end | |
sorted_items.each do |name, weight| | |
min_box = boxes.min { |v1, v2| v1[:weight] <=> v2[:weight] } | |
min_box[:name] << name | |
min_box[:weight] += weight | |
end | |
boxes.each.with_index(1) do |box, index| | |
puts "box#{index}" | |
puts "\tnames: #{box[:name].join(',')}" | |
puts "\tweight: #{box[:weight]}" | |
end | |
# Output: | |
# | |
# box1 | |
# names: bar,hoge | |
# weight: 9 | |
# box2 | |
# names: gongo,fuga,dududu | |
# weight: 8 | |
# box3 | |
# names: hago,piyo,baz,foo | |
# weight: 8 |
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