Created
May 12, 2010 19:57
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| # Given such a DB structure (MySQL): | |
| # | |
| # Table: module_cms_articles | |
| # | |
| # id | version_since | version_until | creation_date | creator_id | title | lead | content | visible | |
| # ----+---------------------+---------------------+---------------------+------------+-----------------------+-----------------+--------------------------+--------- | |
| # 1 | 2010-05-12 19:57:05 | 2010-05-12 20:15:20 | 2010-05-12 19:57:05 | 1 | 1-st article | Introduction... | First article. | 0 | |
| # 1 | 2010-05-12 20:15:20 | 2010-05-12 20:27:28 | 2010-05-12 19:57:05 | 1 | 1-st article | Introduction... | First article. Extended. | 0 | |
| # 1 | 2010-05-12 20:27:28 | 2037-12-31 23:59:59 | 2010-05-12 19:57:05 | 1 | 1-st article modified | Introduction... | First Article. Extended. | 0 | |
| -- 1. Find the most recent version for article with id = 1: | |
| SELECT a.* FROM `module_cms_articles` a LEFT JOIN `module_cms_articles` a_next ON ( a.id = a_next.id AND a_next.version_since > a.version_since ) WHERE a.id = 1 AND a_next.id IS NULL | |
| # id | version_since | version_until | creation_date | creator_id | title | lead | content | visible | |
| # ----+---------------------+---------------------+---------------------+------------+-----------------------+-----------------+--------------------------+--------- | |
| # 1 | 2010-05-12 20:27:28 | 2037-12-31 23:59:59 | 2010-05-12 19:57:05 | 1 | 1-st article modified | Introduction... | First Article. Extended. | 0 | |
| -- 2. Find the most recent version for article with id = 1 from a given date range (e.g. for date range '2010-05-12 20:10:00' - '2010-05-12 20:20:00' version 2 should be returned): | |
| -- 3. Find a version for article with id = 1 that existed on a given date (e.g. for date '2010-05-12 20:20:00' version 2 should be returned): | |
| -- 4. Find the most recent version for article with id = 1 and simultaneously return version_since from the earliest version (thus the creation_date column becomes redundant): |
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