list, set, dictionary comprehension exercises

comprehensions.py

#create a LIST of characters in string 'hello'
my_list = [i for i in 'hello']
print("my_list "+ str(my_list))

#create a LIST of numbers in tuple (1,2,3,4)
new_tuple = [i for i in (1,2,3,4)]
print("new_tuple " + str(new_tuple))

#create a SET of unique items from string
a_set = {i for i in 'hello'}
print("a_set " + str(a_set)) 

#create a LIST of characters in string 'hello'
string = []
for i in 'hello':
  string.append(i)
print(string)

#create a LIST of numbers in range(0,100)
my_list2 = [num for num in range(0,100)]
print("my_list2 " + str(my_list2))

#create a LIST of numbers**2 in range(0,100)
my_list3 = [num**2 for num in range(0,100)]
print("my_list3 " + str(my_list3))

#create a LIST of even numbers**2 in range(0,100)
my_list4 = [num**2 for num in range(0,100) if num%2 ==0]
print("my_list4 " + str(my_list4))

#create a SET of numbers in range(0,100)
my_list5 = {num for num in range(0,100)}
print("my_list5 " + str(my_list5))

#using a sample_dict create a new dictionary where each value will be squared
simple_dict = {
  'a':1,
  'b':2,
  'c':3
}
my_dict = {key:value**2 for key, value in simple_dict.items() }
print("my_dict " + str(my_dict))

#using a sample_dict create a new dictionary where each value will be squared, return only even numbers
your_dict = {k:v**2 for k, v in simple_dict.items()if v%2 ==0 }
print("your_dict " + str(your_dict))

#create a SET of numbers from list [1,2,3] where each item will be multiplied by 2
my_dictr = {i:i*2 for i in [1,2,3]}
print("my_dictr " + str(my_dictr))

#create a new LIST of duplicates from some_list
some_list = ['a', 'b', 'c', 'd', 'e', 'f','a', 'b', 'c','a', 'b', 'c' ]
dupl=[]
new = [dupl.append(i) for i in some_list if some_list.count(i)>1 if i not in dupl]
print(dupl)

#OR
new = list(set([i for i in some_list if some_list.count(i)>1]))
print(dupl)

#create a new SET of duplicates from some_list
duplicates = set([i for i in some_list if some_list.count(i)>1])
print(duplicates)