Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not.

gistfile1.java

public class Solution {
   public boolean isValid(String s) {
      int length=s.length(); 
      char [] array=s.toCharArray();
      if(length==0) return true; 
      Stack<Character> stack=new Stack<Character>(); 
      for(int i=0; i<length; i++)
      {
        if(array[i]=='(' || array[i]=='{' || array[i]=='[' )
        {
          stack.push(array[i]);
        }
        if(array[i]==')' ||array[i]=='}' ||array[i]==']')
        {
          if(stack.isEmpty()) return false; 
          char temp=stack.pop(); 
          if((temp=='(' && array[i]==')' ) || (temp=='{' && array[i]=='}' ) ||(temp=='[' && array[i]==']' )  )
          {
              continue;
          }else
          {
              return false; 
          }
        }
      }
      if(!stack.isEmpty()) return false; 
      return true;        
    }
}

how about this?

const isValid = function (s: string) {
let isTrue = true;
if (s.length % 2 === 0) {
let currentPointer = 0;
for (let i = 0; i < s.length; i++) {
let selectedPair = s.substring(currentPointer, currentPointer + 2);
if (
(selectedPair.length > 1 && selectedPair === '()') ||
selectedPair === '{}' || selectedPair === '[]'
) {
if (currentPointer + 4 <= s.length) {
currentPointer = currentPointer + 2;
}
} else {
isTrue = false;
}
}
} else {
isTrue = false;
}
console.log(isTrue);
};