Python: execute a function with timeout using signals

exec_function_timeout_signal.py

#!/usr/bin/env python

import signal
import time

class SigalrmException(Exception):
	pass 

def sigalrm_handler(signum, frame):
	raise SigalrmException()


def fn_loop_count(message, start_count, end_count):
	for i in range(start_count, end_count):
		print(message + ": " + str(i))
		start_count +=1
		time.sleep(1)
	
	return "OK"


def exec_with_timeout(function_name, args, timeout):
	signal.signal(signal.SIGALRM, sigalrm_handler)
	
	signal.alarm(timeout)
	try:
		retval = function_name(*args) # Convert tuple in args
		return retval
	except SigalrmException:
		retval = None
	
	signal.alarm(0)
	return retval


if __name__ == "__main__":
	
	args = ("Hola Mundo", 10, 12, )
	status = exec_with_timeout(fn_loop_count, args, 5)
	print("Status: {}".format(status))
	
	args = ("Hola Mundo", 50, 100, )
	status = exec_with_timeout(fn_loop_count, args, 5)
	print("Status: {}".format(status))