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December 10, 2017 06:22
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java string match
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import java.util.*; | |
import java.util.regex.*; | |
class NumRegex | |
{ | |
public static void main(String args[]) | |
{ | |
// Create a regular expression that matches | |
// any number You know all this! This is why you came here ;) | |
// What matches and what doesn't? | |
// 1 matches | |
// 24133242 matches | |
// 2342332d doesn't match (it contains d at last!) | |
// 23432 233 doesn't match (it contains a space) | |
// asdfsafd doesn't match (it is not a number) | |
// What's the +? | |
// More 1 or more than 1 digit | |
// \\d is for a signle digit | |
String numRegex="^[\\d]+$"; | |
// This is another way, isn't it lengthy? | |
// Yet, remember it! | |
// String numRegex="^[0-9]+$"; | |
// Hmm, one more. What if i want only a 2 digit number | |
// Replace 2 with whatever you no.of digits you want in | |
// the number. | |
// String numRegex="^[\\d]{2}$"; | |
// Create a Scanner object | |
Scanner s=new Scanner(System.in); | |
// Give the regex for compilation. | |
// Don't worry, it gives a Pattern object in return! ;) | |
Pattern p=Pattern.compile(numRegex); | |
// Ask the user to enter a number, else he | |
// scratches his head of what to do! | |
System.out.println("Enter the number"); | |
// Read a line, use nextLine(). If you forgot | |
// Line and simply use next(), you don't get spaces! | |
String st=s.nextLine(); | |
// Create a Matcher, not a match box! ;) | |
// See if what user has given is a number! | |
Matcher m=p.matcher(st); | |
// Now, print whether the user understood what we said! | |
System.out.println(m.matches()?"You entered a number! Great! you understood the question :)":"I asked for number!!!!"); | |
} | |
} |
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