Created
November 14, 2018 00:04
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facebook interview, task schedule
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def calc_task_time1(tasks): | |
# use a dict, keep all task last run time | |
# more space used, less run time expected | |
time = 0 | |
d = dict() | |
for t in tasks: | |
if t in d: | |
last = d[t] | |
time = max(last + n, time) + 1 | |
else: | |
time += 1 | |
d[t] = time | |
return time | |
def calc_task_time1(tasks): | |
time = 0 | |
q = deque() | |
d = set() | |
tasks = tasks[::-1] | |
while tasks: | |
t = tasks.pop() | |
if t in q: | |
q.append(None) | |
tasks.append(t) | |
else: | |
q.append(t) | |
if len(q) >= n + 1: | |
q.popleft() | |
time += 1 | |
return time |
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