-
-
Save hahastudio/4bca83824d594db350a3e90e538f1171 to your computer and use it in GitHub Desktop.
Excel表格密码保护的解除方法
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
表格受密码保护时,我们修改数据Excel弹出“您试图更改的单元格或图表受保护,因而是只读的。 | |
若要修改受保护单元格或图表,请先使用‘撤消工作表保护’命令(在‘审阅’选项卡的‘更改’组中)来取消保护。 | |
可能会提示输入密码。这时候我们可以用VBA宏代码破解法来破解表格保护密码: | |
第一步:打开该文件,先解除默认的“宏禁用”状态,方法是点击工具栏下的“选项”状态按钮, | |
打开“Microsoft Office安全选项”窗口,选择其中的“启用此内容”,“确定” | |
再切换到“视图”选项卡,点击“宏”→“录制宏”,出现“录制新宏”窗口,在“宏名”定义一个名称为: | |
PasswordBreaker,点击“确定”退出; | |
第二步:再点击“宏”→“查看宏”,选择“宏名”下的“PasswordBreaker”并点击“编辑”, | |
打开“Microsoft Visual Basic”编辑器,用如下内容替换右侧窗口中的所有代码: | |
Sub PasswordBreaker() | |
Dim i As Integer, j As Integer, k As Integer | |
Dim l As Integer, m As Integer, n As Integer | |
Dim i1 As Integer, i2 As Integer, i3 As Integer | |
Dim i4 As Integer, i5 As Integer, i6 As Integer | |
On Error Resume Next | |
For i = 65 To 66: For j = 65 To 66: For k = 65 To 66 | |
For l = 65 To 66: For m = 65 To 66: For i1 = 65 To 66 | |
For i2 = 65 To 66: For i3 = 65 To 66: For i4 = 65 To 66 | |
For i5 = 65 To 66: For i6 = 65 To 66: For n = 32 To 126 | |
ActiveSheet.Unprotect Chr(i) & Chr(j) & Chr(k) & _ | |
Chr(l) & Chr(m) & Chr(i1) & Chr(i2) & Chr(i3) & _ | |
Chr(i4) & Chr(i5) & Chr(i6) & Chr(n) | |
If ActiveSheet.ProtectContents = False Then | |
MsgBox "One usable password is " & Chr(i) & Chr(j) & _ | |
Chr(k) & Chr(l) & Chr(m) & Chr(i1) & Chr(i2) & _ | |
Chr(i3) & Chr(i4) & Chr(i5) & Chr(i6) & Chr(n) | |
ActiveWorkbook.Sheets(1).Select | |
Range("a1").FormulaR1C1 = Chr(i) & Chr(j) & _ | |
Chr(k) & Chr(l) & Chr(m) & Chr(i1) & Chr(i2) & _ | |
Chr(i3) & Chr(i4) & Chr(i5) & Chr(i6) & Chr(n) | |
Exit Sub | |
End If | |
Next: Next: Next: Next: Next: Next | |
Next: Next: Next: Next: Next: Next | |
End Sub | |
第三步:再点击“宏”→“查看宏”,选择“宏名”下的“PasswordBreaker”并点击“执行”,密码就现形了 | |
第四步:点击“撤消工作表保护”,然后输入密码即可解除锁定; | |
测试结果,密码破解可用,但是很晕的是破解的密码跟原来的密码有很大的差距,想不明白了,反正能用就好。 |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment