multiples-of-three-and-five.js

// If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

// Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in.

// Note: If the number is a multiple of both 3 and 5, only count it once.

function solution(number){
    const arr = []
    for(i = 1; i < number; i++) {
        arr.push(i)
    }
    const sumArr = []
    arr.forEach(function(number) {
        if (number % 3 === 0 || number % 5 === 0) {
            sumArr.push(number)
        }
    })
    if (sumArr.indexOf(sumArr[0]) === -1) {
        return 0
    }
    const result = sumArr.reduce(function(acc, cv) {
        return acc + cv
    })
    return result
}

console.log(solution(11))