Created
May 24, 2021 09:17
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Generate true Reber grammar sequences.
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# This Python script can be used to generate true Reber grammar sequences. | |
# To generate false Reber grammar sequences, just change tuple values in 'traversal' at line 8. | |
import numpy as np | |
chars = 'BTSXPVE' | |
traversal = [[('T', 'P'), (1, 4)], [('S', 'X'), (1, 2)], [('S', 'X'), (3, 4)], [('E'), (-1,)], [('V', 'T'), (5, 4)], [('V', 'P'), (3, 2)]] | |
def generate_seq(min_length): | |
while True: | |
seq = ['B'] | |
node = 0 | |
while node is not -1: | |
trans = traversal[node] | |
index = np.random.randint(0, len(trans[0])) | |
seq.append(trans[0][index]) | |
node = trans[1][index] | |
if len(seq) > min_length: | |
return ''.join(seq) | |
def check_seq(seq): | |
seq = list(seq.upper()) | |
if seq[0] is not 'B': | |
return False | |
node = 0 | |
for s in seq[1:]: | |
trans = traversal[node] | |
try: | |
index = trans[0].index(s) | |
node = trans[1][index] | |
except ValueError: | |
return False | |
return True | |
def to_one_hot(seq): | |
seq = list(seq) | |
in_seq = [] | |
for c in seq: | |
encoded = np.zeros(7) | |
encoded[chars.find(c)] = 1. | |
in_seq.append(encoded) | |
out_seq = in_seq[1:] | |
in_seq = in_seq[0:-1] | |
return in_seq, out_seq | |
def to_string(seq): | |
reber_string = '' | |
for s in seq: | |
index = np.where(s==1.)[0][0] | |
reber_string += chars[index] | |
return reber_string |
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