Spiral Matrix Code in JS

gistfile1.txt

function spiralOrder(matrix) {
  if (!matrix.length || !matrix[0].length) return [];

  const result = [];
  const rows = matrix.length, cols = matrix[0].length;
  let top = 0, bottom = rows - 1, left = 0, right = cols - 1;

  while (top <= bottom && left <= right) {
    // Traverse right
    for (let i = left; i <= right; i++) {
      result.push(matrix[top][i]);
    }
    top++;

    // Traverse down
    for (let i = top; i <= bottom; i++) {
      result.push(matrix[i][right]);
    }
    right--;

    // Traverse left (only if there are more elements in the row)
    if (top <= bottom) {
      for (let i = right; i >= left; i--) {
        result.push(matrix[bottom][i]);
      }
      bottom--;
    }

    // Traverse up (only if there are more elements in the column)
    if (left <= right) {
      for (let i = bottom; i >= top; i--) {
        result.push(matrix[i][left]);
      }
      left++;
    }
  }

  return result;
}


const matrix = 
[[1,2,3],
[4,5,6],
[7,8,9] ];

const response = spiralOrder(matrix)
console.log(response);