Solution for problem "Given an array of words, group them by word length, then sort within each group based on the number of vowels in the word (descending), and finally, for ties, use alphabetical order (case-insensitive)"

index.js

const wordGroup = [
    "apple", "orange", "pear", "grape",
    "kiwi", "Avocado", "banana", "fig", "Apricot"
];

const getVowelCount = (str) => {
    const vowels = ["a", "e", "i", "o", "u"];    
    let vowelCount = 0;

    for(let i = 0; i < str.length; i++){
        if(vowels.includes(str[i].toLowerCase())){
            vowelCount++;
        }
    }
    return vowelCount
};

const getSortedArrayByWordCount = (wordCount, arr) => {
    const filteredArrayByWordCount = arr.filter((elem) => elem.length === wordCount);
    const result = [];
    
    filteredArrayByWordCount.forEach((elem) => {
        if(!result.length) {
            result.push(elem)
            return;
        }
        
        for(let i = 0; i < result.length; i++){
            const elemVowelCount = getVowelCount(elem);
            const iVowelCount = getVowelCount(result[i]);
            
            if(elemVowelCount > iVowelCount){
                result.splice(i, 0, elem);
                break;
            }
            
            if(elemVowelCount === iVowelCount) {
               if(result[i].toLowerCase() > elem.toLowerCase()) {
                   result.splice(i, 0, elem)
                   break;
               }
            }
            
            
            if(i === result.length - 1) {
                result.push(elem)
                break;
            }
        }
    })
    
    return result;
}

const sort = (arr) => {
    return [...arr].reduce((acc, curr) => {
        if(!acc[curr.length]){
            acc[curr.length] = getSortedArrayByWordCount(curr.length, arr);
        }
        
        return acc;
    }, {})
}