Created
February 4, 2014 06:08
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Fast SQLAlchemy counting (avoid query.count() subquery)
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def get_count(q): | |
count_q = q.statement.with_only_columns([func.count()]).order_by(None) | |
count = q.session.execute(count_q).scalar() | |
return count | |
q = session.query(TestModel).filter(...).order_by(...) | |
# Slow: SELECT COUNT(*) FROM (SELECT ... FROM TestModel WHERE ...) ... | |
print q.count() | |
# Fast: SELECT COUNT(*) FROM TestModel WHERE ... | |
print get_count(q) |
If you find your query executing slow, the first is to try removing order by.
I tried this, and the methods outlined in the stackoverflow link, and it did not work. Please don't say I'm providing misinformation
by outlining what worked for me it is rude.
Sorry for letting you misunderstand. I meant the gist (which was posted in 2015) is likely misinformation now, not your comment.
This is the method, I'm using
def get_count(self, model_fields, filter_clause):
""" Note: filter_clause should not be 'None' or 'Null' for this method to work """
query = self.session.query().with_entities(*model_fields)
query = query.filter(filter_clause)
count_query = query.statement \
.with_only_columns([func.count()]) \
.order_by(None)
result = query.session.execute(count_query).scalar()
return result
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This thread is generally a kind of misinformation. If you check the stackoverflow link above, these sqls are exactly the same:
If you find your query executing slow, the first is to try removing
order by
.