Created
November 16, 2018 19:12
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c: test: *p++ = v; is what we will probably want setting values in the loop
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| // all the same: | |
| // *p++ = x | |
| // *(p)++ = x | |
| // *(p++) = x | |
| // | |
| #include <stdio.h> | |
| void print_arr(int a[]) | |
| { | |
| for(int i=0; i<3; i++) { | |
| printf("%d\n", a[i]); | |
| } | |
| } | |
| void set_arr(int *p, int v1, int v2, int v3) | |
| { | |
| *p++ = v1; | |
| *p++ = v2; | |
| *p++ = v3; | |
| } | |
| void set_arr2(int *p, int v1, int v2, int v3) | |
| { | |
| *(p)++ = v1; | |
| *(p)++ = v2; | |
| *(p)++ = v3; | |
| } | |
| void set_arr3(int *p, int v1, int v2, int v3) | |
| { | |
| *(p++) = v1; | |
| *(p++) = v2; | |
| *(p++) = v3; | |
| } | |
| #if 0 | |
| void set_arr4(int *p, int v1, int v2, int v3) | |
| { | |
| (*p)++ = v1; // error: expression is not assignable | |
| (*p)++ = v2; // error: expression is not assignable | |
| (*p)++ = v3; // error: expression is not assignable | |
| } | |
| #endif | |
| int main(void) | |
| { | |
| int arr[3]; | |
| int *parr = arr; | |
| set_arr(parr, 3, 2, 1); | |
| print_arr(arr); | |
| printf("---------\n"); | |
| set_arr2(parr, 6, 5, 4); | |
| print_arr(arr); | |
| printf("---------\n"); | |
| set_arr3(parr, 9, 8, 7); | |
| print_arr(arr); | |
| #if 0 // error occured | |
| set_arr4(parr, 111, 444, 777); | |
| print_arr(arr); | |
| #endif | |
| return 0; | |
| } | |
| // result | |
| // ---------------------------------- | |
| // ~/test/c ❯❯❯ gcc ptr_plus_plus.c && ./a.out | |
| // 3 | |
| // 2 | |
| // 1 | |
| // --------- | |
| // 6 | |
| // 5 | |
| // 4 | |
| // --------- | |
| // 9 | |
| // 8 | |
| // 7 | |
| // ~/test/c ❯❯❯ | |
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