Created
March 17, 2017 22:25
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Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
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public class Solution { | |
public int maxSubArray(int[] nums) { | |
if(nums.length == 0){ | |
return 0; | |
} | |
int[] sum = new int[nums.length]; | |
int[] indices = new int[nums.length]; | |
sum[0] = nums[0]; | |
indices[0] = 0; | |
for(int i = 1 ; i < nums.length ; ++i){ | |
if(sum[i-1]+nums[i] >= nums[i]){ | |
sum[i] = sum[i-1]+nums[i]; | |
}else{ | |
sum[i] = nums[i]; | |
indices[i] = i; | |
} | |
} | |
int maxSum = sum[0]; | |
int index = 0; | |
for(int j = 1 ; j < sum.length ; ++j){ | |
if(sum[j] >= maxSum){ | |
maxSum = sum[j]; | |
index = j; | |
} | |
} | |
return maxSum; | |
} | |
} |
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