Did you know that bash will reload a script *while it is executing*?!

test.sh

#!/bin/bash

function addnext {
	NUM=$1
	sleep 1
	echo HI $NUM
	NUM=$(expr $NUM + 1)
	echo addnext $NUM >> $0
}

addnext 1

nothing is surprising about this. bash doesn't need to preprocess its source (there's no bash vm) so why would it first buffer the entire file (which could be very large)?

even if it did buffer the entire file, it would pick up new changes as the file was appended to as it was buffering.

Not to split hairs here, but because the file lacks an EOL, this does not work until you edit the file and add a \n to it.

curl -LO https://gist.githubusercontent.com/hmason/3419831/raw/test.sh; chmod +x ./test.sh; ./test.sh

In other words...

$ curl -LO https://gist.githubusercontent.com/hmason/3419831/raw/test.sh; chmod +x test.sh; ./test.sh
  % Total    % Received % Xferd  Average Speed   Time    Time     Time  Current
                                 Dload  Upload   Total   Spent    Left  Speed
100   122  100   122    0     0    346      0 --:--:-- --:--:-- --:--:--   346
HI 1

$ cat test.sh
#!/bin/bash

function addnext {
	NUM=$1
	sleep 1
	echo HI $NUM
	NUM=$(expr $NUM + 1)
	echo addnext $NUM >> $0
}

addnext 1addnext 2

$ curl -LO https://gist.githubusercontent.com/hmason/3419831/raw/test.sh; chmod +x test.sh; echo >> test.sh; ./test.sh
  % Total    % Received % Xferd  Average Speed   Time    Time     Time  Current
                                 Dload  Upload   Total   Spent    Left  Speed
100   122  100   122    0     0    321      0 --:--:-- --:--:-- --:--:--   321
HI 1
HI 2
HI 3
HI 4
HI 5
HI 6
HI 7
HI 8
HI 9
HI 10
...

A simple strace shows that it is not reloading anything.

script:

#!/bin/bash

num=0

while [[ $num -lt 20 ]] ; do
        echo "waiting...$num"
        sleep 1s
        num=$(( $num + 1 ))
done


echo "I am done!"

open("./run.sh", O_RDONLY)              = 3
ioctl(3, SNDCTL_TMR_TIMEBASE or SNDRV_TIMER_IOCTL_NEXT_DEVICE or TCGETS, 0x7ffda02d2010) = -1 ENOTTY (Inappropriate ioctl for device)
lseek(3, 0, SEEK_CUR)                   = 0
read(3, "#!/bin/bash\n\nnum=0\n\nwhile [[ $nu"..., 80) = 80
lseek(3, 0, SEEK_SET)                   = 0
getrlimit(RLIMIT_NOFILE, {rlim_cur=1024, rlim_max=4*1024}) = 0
fcntl(255, F_GETFD)                     = -1 EBADF (Bad file descriptor)
dup2(3, 255)                            = 255
close(3)                                = 0
fcntl(255, F_SETFD, FD_CLOEXEC)         = 0
fcntl(255, F_GETFL)                     = 0x8000 (flags O_RDONLY|O_LARGEFILE)
fstat(255, {st_mode=S_IFREG|0775, st_size=128, ...}) = 0
lseek(255, 0, SEEK_CUR)                 = 0
...
read(255, "#!/bin/bash\n\nnum=0\n\nwhile [[ $nu"..., 128) = 128
...
lseek(255, -20, SEEK_CUR)               = 108
...
read(255, "\n\necho \"I am done!\"\n", 128) = 20
read(255, "", 128)                      = 0
exit_group(0)                           = ?

I did not check bash source code but I would imagine it would never read the entire script in memory. It should read it by chunks as it executes it. I am not sure why it does that lseek() but probably just to go to the beginning of the last line and continue reading from there. Just a guess. So, the behaviour of the script "changing" one the fly would depend on how the filesystem react to the concurrent reading and writing.

I may be wrong, this is just my guess based on what I would expect and what I see in strace on Linux....