Created
November 10, 2017 18:00
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/** | |
* Created by Hoan Nguyen on 11/11/2017. | |
*/ | |
//Note that: this solution is for array of Intergers ONLY | |
function diffArray(arr1, arr2) { | |
var output = []; | |
// Same, same; but different. | |
arr1.sort((a, b) => a - b); | |
arr2.sort((a, b) => a - b); | |
var i = 0, j = 0; | |
while (true) { | |
if (arr1[i] < arr2[j]) { | |
output.push(arr1[i]); | |
i++; | |
} else if (arr1[i] > arr2[j]) { | |
output.push(arr2[j]); | |
j++; | |
} else { | |
i++; | |
j++; | |
} | |
if (i == arr1.length && j == arr2.length) break; | |
if (i == arr1.length && j < arr2.length) { | |
for (var x = j; x < arr2.length; x++) { | |
output.push(arr2[x]); | |
} | |
break; | |
} | |
if (j == arr2.length && i < arr1.length) { | |
for (var y = i; y < arr1.length; y++) { | |
output.push(arr1[y]); | |
} | |
break; | |
} | |
} | |
return output; | |
} | |
function findDifference(arr1, arr2) { | |
var a = Array.from(new Set(arr1)); | |
var b = Array.from(new Set(arr2)); | |
var map = new Map(); | |
var output = []; | |
for (var i = 0; i < a.length; i++) { | |
map.set(a[i], 1); | |
} | |
for (var i = 0; i < b.length; i++) { | |
if (map.has(b[i])) { | |
map.set(b[i], map.get(b[i]) + 1); | |
} else { | |
map.set(b[i], 1); | |
} | |
} | |
var keys = Array.from(map.keys()); | |
for (var i = 0; i < keys.length; i++) { | |
if (map.get(keys[i]) === 1) output.push(keys[i]); | |
} | |
return output; | |
} | |
// diffArray([1, 4, 3, 5], [1, 2, 3, 4, 5, 8]); | |
console.log(diffArray([1, 4, 3, 5, 10], [1, 2, 3, 4, 5, 8])); | |
// console.log(diffArray([1, 4, 3, 10], [1, 2, 3, 4, 5])); | |
console.log(findDifference([1, 4, 3, 5, 10], [1, 2, 2, 3, 4, 5, 8])); | |
console.log(findDifference(["diorite", "andesite", "grass", "dirt", "pink wool", "dead shrub"], ["diorite", "andesite", "grass", "dirt", "dead shrub"])); | |
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