Created
May 12, 2014 03:43
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| public class Solution { | |
| public ArrayList <ArrayList<String>> partition(String s) { | |
| ArrayList <ArrayList<String>> ret = new ArrayList <ArrayList<String>>(); | |
| if (s == null || s=="") | |
| return ret; | |
| ArrayList<String> palindrome = new ArrayList<String>(); | |
| addPalindrome(s, 0, palindrome, ret); | |
| return ret; | |
| } | |
| public void addPalindrome(String s, int start, ArrayList<String> p, | |
| ArrayList <ArrayList<String>> ret) { | |
| int e = s.length(); | |
| if (start == e) { | |
| ArrayList <String> temp = new ArrayList<String>(p); | |
| ret.add(temp); | |
| return; | |
| } | |
| for (int i = start + 1; i <= e; i++) { | |
| String str = s.substring(start, i); | |
| if (isPalindrome(str)) { | |
| p.add(str); | |
| addPalindrome(s, i, p, ret); | |
| //if comment this, fun | |
| p.remove(p.size() - 1); | |
| } | |
| } | |
| } | |
| public boolean isPalindrome(String s) { | |
| int i = 0; | |
| int e = s.length() - 1; | |
| while (i < e) { | |
| if(s.charAt(i++) != s.charAt(e--)) | |
| return false; | |
| } | |
| return true; | |
| } | |
| } |
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