Quickly find project directories which have the fewest test files (really just fewest files)

gistfile1.sh

for i in $(find . -name '*TestMain.cpp' -exec dirname {} \; | sort | uniq); do
  echo "$(find $i -type f -depth 1 -maxdepth 1 | wc -l) $i";
done | sort -n | head

How about this?

find . -name "*TestMain.cpp" | sed 's,/[^/]*$,,' | sort | uniq -c | sort -n | head

That just counts unique directory path names? I was wanting to count the number of files in any directory that contains a *TestMain.cpp file

…

On Aug 11, 2011, at 11:27 PM, magnusstahre wrote: How about this? find . -name "_TestMain.cpp" | sed 's,/[^/]_$,,' | sort | uniq -c | sort -n ## Reply to this email directly or view it on GitHub: https://gist.github.com/1139459

Good point. One thing to remember is that you are counting subdirectories as well as files now; if you just want to count files in a directory you can do something like

find $i -type f -depth 1 -maxdepth 1 | wc -l

I like that better - thanks Magnus!