Created
March 21, 2014 10:06
-
-
Save housemeow/9683080 to your computer and use it in GitHub Desktop.
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
#include <stdio.h> | |
#include <stdlib.h> | |
#include <string.h> | |
void input(char* string1, char* string2, char* string3); | |
void englishExample(char* string1, char* string2, char* string3); | |
int isMain(char* string); | |
int isVerb(char* string); | |
int isHaveToAddS(char* main); | |
int main() | |
{ | |
while(1){ | |
char string1[100]; | |
char string2[100]; | |
char string3[100]; | |
input(string1, string2, string3); | |
englishExample(string1, string2, string3); | |
puts(string1); | |
puts(string2); | |
puts(string3); | |
system("pause"); | |
} | |
return 0; | |
} | |
void input(char* string1, char* string2, char* string3) | |
{ | |
scanf("%s%s%s", string1, string2, string3); | |
} | |
void englishExample(char* string1, char* string2, char* string3) | |
{ | |
char* main[2]; | |
int mainCount = 0; | |
char* verb; | |
printf("%s isMain result = %d\n", string1, isMain(string1)); | |
printf("%s isMain result = %d\n", string2, isMain(string2)); | |
printf("%s isMain result = %d\n", string3, isMain(string3)); | |
printf("%s isVerb result = %d\n", string1, isVerb(string1)); | |
printf("%s isVerb result = %d\n", string2, isVerb(string2)); | |
printf("%s isVerb result = %d\n", string3, isVerb(string3)); | |
if(isMain(string1)) | |
{ | |
main[mainCount++] = string1; | |
} | |
if(isMain(string2)){ | |
main[mainCount++] = string2; | |
} | |
if(isMain(string3)){ | |
main[mainCount++] = string3; | |
} | |
if(isVerb(string1)) | |
{ | |
verb = string1; | |
}else if(isVerb(string2)){ | |
verb = string2; | |
}else if(isVerb(string3)){ | |
verb = string3; | |
} | |
printf("%s isHaveToAddS result = %d\n", string1, isHaveToAddS(string1)); | |
printf("%s isHaveToAddS result = %d\n", string2, isHaveToAddS(string2)); | |
printf("%s isHaveToAddS result = %d\n", string3, isHaveToAddS(string3)); | |
int mainIndex; | |
for(mainIndex=0;mainIndex<mainCount;mainIndex++){ | |
printf("%s", main[mainIndex]); | |
if(isHaveToAddS(main[mainIndex])){ | |
printf(" %ss\n", verb); | |
}else{ | |
printf(" %s\n", verb); | |
} | |
} | |
} | |
int isMain(char* string) | |
{ | |
char mains[][10] = {"I", "He", "She", "They", "Mary", "John"}; | |
int mainsCount = 6; | |
int mainIndex; | |
for(mainIndex=0;mainIndex<mainsCount;mainIndex++){ | |
if(strcmp(string, mains[mainIndex])==0){ | |
return 1; | |
} | |
} | |
return 0; | |
} | |
int isVerb(char* string) | |
{ char verbs[][10] = {"love", "like", "see", "find"}; | |
int verbsCount = 4; | |
int verbsIndex; | |
for(verbsIndex=0;verbsIndex<verbsCount;verbsIndex++){ | |
if(strcmp(string, verbs[verbsIndex])==0){ | |
return 1; | |
} | |
} | |
return 0; | |
} | |
int isHaveToAddS(char* main) | |
{ | |
char mains[][10] = {"He", "She", "Mary", "John"}; | |
int mainsCount = 4; | |
int mainIndex; | |
for(mainIndex=0;mainIndex<mainsCount;mainIndex++){ | |
if(strcmp(main, mains[mainIndex])==0){ | |
return 1; | |
} | |
} | |
return 0; | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment