extern of array

data.c

extern char array[] = {1, 2, 3, 4};

rightref.c

// This is the right way of reference an extern array
extern char array[];

int main()
{
   array[0] = 0;
   array[1] = 1;
}

wrongref.c

// compile pass, but in runtime, it would be a seg fault because:
// char* and char[] are of different types, actually, it will interpreted as
// array is a pointer with its address equals the real array's content.
// so here char* points to 04030201.
//

extern char* array;

int main()
{
   array[0] = 0;
   array[1] = 1;
}