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April 15, 2017 14:52
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In Binary Search Tree two nodes are out of order
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| package com.hrishikesh.practices.binarysearchtree; | |
| import com.hrishikesh.practices.binarytree.BTPrinter; | |
| import com.hrishikesh.practices.binarytree.BinaryTreeNode; | |
| import java.util.Objects; | |
| /** | |
| * Problem: | |
| * In Binary Search Tree two nodes are out of order | |
| * ; | |
| * In given binary search tree two nodes are swapped, fix this. | |
| * | |
| * @author hrishikesh.mishra | |
| */ | |
| public class BinarySearchTreeTwoOutOfOrderNode { | |
| private static class Nodes { | |
| private BinaryTreeNode<Integer> previousNode; | |
| private BinaryTreeNode<Integer> firstSwappedNode; | |
| private BinaryTreeNode<Integer> secondSwappedNode; | |
| } | |
| public static void fix(BinaryTreeNode<Integer> root) { | |
| Nodes nodes = new Nodes(); | |
| fixHelper(root, nodes); | |
| BinaryTreeNode<Integer> firstNode = nodes.firstSwappedNode; | |
| BinaryTreeNode<Integer> secondNode = nodes.secondSwappedNode; | |
| if (!Objects.isNull(firstNode) && !Objects.isNull(secondNode)) { | |
| int temp = firstNode.getData(); | |
| firstNode.setData(secondNode.getData()); | |
| secondNode.setData(temp); | |
| } | |
| } | |
| private static void fixHelper(BinaryTreeNode<Integer> node, Nodes nodes) { | |
| if (Objects.isNull(node)) { | |
| return; | |
| } | |
| fixHelper(node.getLeft(), nodes); | |
| checkNodeValues(node, nodes); | |
| nodes.previousNode = node; | |
| fixHelper(node.getRight(), nodes); | |
| } | |
| private static void checkNodeValues(BinaryTreeNode<Integer> node, Nodes nodes) { | |
| if (Objects.isNull(nodes.previousNode)) { | |
| return; | |
| } | |
| if (node.getData() < nodes.previousNode.getData()) { | |
| addInvalidNode(nodes.previousNode, node, nodes); | |
| } | |
| } | |
| private static void addInvalidNode(BinaryTreeNode<Integer> node1 , | |
| BinaryTreeNode<Integer> node2, Nodes nodes) { | |
| if (Objects.isNull(nodes.firstSwappedNode)) { | |
| nodes.firstSwappedNode = node1; | |
| } else if (Objects.isNull(nodes.secondSwappedNode)) { | |
| nodes.secondSwappedNode = node2; | |
| } else { | |
| throw new RuntimeException("More than two nodes are invalid!"); | |
| } | |
| } | |
| } | |
| class BinarySearchTreeTwoOutOfOrderNodeTest { | |
| public static void main(String[] args) { | |
| BinaryTreeNode<Integer> root = new BinaryTreeNode<>(100, | |
| new BinaryTreeNode<>(120, | |
| new BinaryTreeNode<>(30), | |
| new BinaryTreeNode<>(80)), | |
| new BinaryTreeNode<>(70, | |
| new BinaryTreeNode<>(110), | |
| new BinaryTreeNode<>(130))); | |
| BTPrinter.print(root); | |
| System.out.print("Before fix: "); | |
| traverseInOrder(root); | |
| BinarySearchTreeTwoOutOfOrderNode.fix(root); | |
| System.out.print("\nAfter fix: "); | |
| traverseInOrder(root); | |
| } | |
| public static void traverseInOrder(BinaryTreeNode<Integer> node) { | |
| if (Objects.isNull(node)) { | |
| return; | |
| } | |
| traverseInOrder(node.getLeft()); | |
| System.out.printf("%d ", node.getData()); | |
| traverseInOrder(node.getRight()); | |
| } | |
| } |
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