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April 15, 2017 15:30
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Minimum Cost Path Finder
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| package com.hrishikesh.practices.dynamicprogramming; | |
| /** | |
| * Problem: | |
| * Minimum Cost Path Finder | |
| * Given a 2D matrix where each cell has a cost to travel. | |
| * Find a path from left-top corner to bottom-right corner with minimum travel cost. | |
| * Constraint: You can move only right or down. | |
| * | |
| * @author hrishikesh.mishra | |
| */ | |
| public class MinimumCostPathFinder { | |
| public static int find(int[][] costMatrix) { | |
| int[][] dpTable = new int[costMatrix.length][costMatrix[0].length]; | |
| /** Top left corner cost **/ | |
| dpTable[0][0] = costMatrix[0][0]; | |
| /** First column cost **/ | |
| for (int i = 1; i < dpTable.length; i++) { | |
| dpTable[i][0] = dpTable[i - 1][0] + costMatrix[i][0]; | |
| } | |
| /** First row cost **/ | |
| for (int i = 1; i < dpTable.length; i++) { | |
| dpTable[0][i] = dpTable[0][i - 1] + costMatrix[0][i]; | |
| } | |
| for (int i = 1; i < dpTable.length; i++) { | |
| for (int j = 1; j < dpTable[i].length; j++) { | |
| dpTable[i][j] = Math.min(dpTable[i][j - 1], dpTable[i - 1][j]) + costMatrix[i][j]; | |
| } | |
| } | |
| return dpTable[dpTable.length - 1][dpTable[0].length - 1]; | |
| } | |
| } | |
| class MinimumCostPathFinderTest { | |
| public static void main(String[] args) { | |
| int[][] costMatrix = { | |
| {1, 7, 9, 2}, | |
| {8, 6, 3, 2}, | |
| {1, 6, 7, 8}, | |
| {2, 9, 8, 2} | |
| }; | |
| printMatrix(costMatrix); | |
| System.out.println("Minimum Cost : " + MinimumCostPathFinder.find(costMatrix)); | |
| } | |
| private static void printMatrix(int[][] costMatrix) { | |
| for (int i = 0; i < costMatrix.length; i++) { | |
| for (int j = 0; j < costMatrix[0].length; j++) { | |
| System.out.printf("%d ", costMatrix[i][j]); | |
| } | |
| System.out.println(); | |
| } | |
| } | |
| } |
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