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April 15, 2017 15:07
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Binary Tree Maximum Path Sum
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package com.hrishikesh.practices.binarytree; | |
import java.util.Objects; | |
/** | |
* Binary Tree Maximum Path Sum | |
* For a binary tree, find the maximum path sum. The path may start and end at any node in the tree. | |
* | |
* @author hrishikesh.mishra | |
*/ | |
public class BinaryTreeMaximumPathSum { | |
private static class Result { | |
int maxValue; | |
public Result(int maxValue) { | |
this.maxValue = maxValue; | |
} | |
} | |
public static int find(BinaryTreeNode<Integer> root) { | |
Result result = new Result(Integer.MIN_VALUE); | |
findHelper(root, result); | |
return result.maxValue; | |
} | |
private static int findHelper(BinaryTreeNode<Integer> node, Result result) { | |
/** Base case: when node is null **/ | |
if (Objects.isNull(node)) { | |
return 0; | |
} | |
int leftMax = findHelper(node.getLeft(), result); | |
int rightMax = findHelper(node.getRight(), result); | |
/** | |
* If max sum path goes through current node then there are four different possible paths | |
* 1. Through node only | |
* 2. Left + Node | |
* 3. Right + Node | |
* 4. Left + Node + Right | |
**/ | |
/** First Three cases | |
* 1. Node, | |
* 2. Node + Left | |
* 3. Node + Right | |
**/ | |
int maxSum = Math.max(Math.max(leftMax, rightMax) + node.getData(), node.getData()); | |
/** | |
* Last Case | |
* Left + Node + Right | |
*/ | |
int newMaxSum = Math.max(maxSum, leftMax + node.getData() + rightMax); | |
/** Updating max result **/ | |
if (newMaxSum > result.maxValue) { | |
result.maxValue = newMaxSum; | |
} | |
return maxSum; | |
} | |
} | |
class BinaryTreeMaximumPathSumTest { | |
public static void main(String[] args) { | |
BinaryTreeNode<Integer> root = new BinaryTreeNode<>(100, | |
new BinaryTreeNode<>(20, | |
new BinaryTreeNode<>(10), | |
new BinaryTreeNode<>(30) | |
), | |
new BinaryTreeNode<>(10, | |
null, | |
new BinaryTreeNode<>(-14, | |
new BinaryTreeNode<>(13), | |
new BinaryTreeNode<>(3)))); | |
BTPrinter.print(root); | |
System.out.println("Maximum Path Sum: " + BinaryTreeMaximumPathSum.find(root)); | |
} | |
} |
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