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Longest palindromic substring in quadratic time O(n^2)
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def longestPalindrome(self, s): | |
""" | |
:type s: str | |
:rtype: str | |
""" | |
best_palindrome_length = 1 | |
best_palindrome = s[0] | |
n = len(s) | |
for i in range(2 * n - 1): | |
if i % 2 == 0: | |
candidate_string = s[i/2] | |
left = i / 2 - 1 | |
right = i / 2 + 1 | |
else: | |
candidate_string = '' | |
left = i / 2 | |
right = i / 2 + 1 | |
while left >= 0 and right < n and s[left] == s[right]: | |
candidate_string = s[left] + candidate_string + s[right] | |
left -= 1 | |
right += 1 | |
if len(candidate_string) > best_palindrome_length: | |
best_palindrome = candidate_string | |
best_palindrome_length = len(candidate_string) | |
return best_palindrome |
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