Last active
May 2, 2024 17:52
-
-
Save hughdbrown/5c13e1338a7d88a2bc9bd990fbd7e4a3 to your computer and use it in GitHub Desktop.
Code to write spiral of integers in a square
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
from itertools import cycle | |
def spiral(n): | |
matrix = [[0] * n for _ in range(n)] | |
x, y = 0, 0 | |
x0, y0, xn, yn = 0, 0, n, n | |
directions = cycle([ | |
(1, 0, (0, 0, 1, 0)), | |
(0, 1, (0, -1, 0, 0)), | |
(-1, 0, (0, 0, 0, -1)), | |
(0, -1, (1, 0, 0, 0)), | |
]) | |
delta_x, delta_y, delta = next(directions) | |
for i in range(1, n * n + 1): | |
matrix[y][x] = i | |
if not (x0 <= (x + delta_x) < xn) or not (y0 <= (y + delta_y) < yn): | |
x0 += delta[0] | |
xn += delta[1] | |
y0 += delta[2] | |
yn += delta[3] | |
delta_x, delta_y, delta = next(directions) | |
x += delta_x | |
y += delta_y | |
for row in matrix: | |
print(" ".join([f"{item:03}" for item in row])) | |
if __name__ == '__main__': | |
spiral(10) |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment