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kubernetes DevOps Operation Script
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BY_LIST_FILE="NONE" | |
COMPLETED="1/." | |
AGE="3" | |
NAME_PATTERN=".*" | |
while [[ $# -gt 0 ]]; do | |
key="$1" | |
case $key in | |
-c|--completed) | |
COMPLETED="$2\/." | |
shift # past argument | |
shift # past value | |
;; | |
-t|--age) | |
AGE="$2" | |
shift # past argument | |
shift # past value | |
;; | |
-n|--name) | |
NAME_PATTERN="$2" | |
shift # past argument | |
shift # past value | |
;; | |
-l|--list) | |
BY_LIST_FILE="$2" | |
shift # past argument | |
shift # past value | |
;; | |
# -f|--force) | |
# FORCE="TRUE" | |
# shift # past argument | |
# ;; | |
# -p|--prep) | |
# PREP="$4" | |
# shift # past argument | |
# ;; | |
# --default) | |
# DEFAULT=YES | |
# shift # past argument | |
# ;; | |
*) # unknown option | |
POSITIONAL+=("$1") # save it in an array for later | |
shift # past argument | |
;; | |
esac | |
done | |
if [ "$BY_LIST_FILE" = "NONE" ] | |
then | |
AGE_PATTERN=$(echo "([$AGE-9]|[1-4][0-9]|50)d") | |
# if age = 0, then also remove jobs less than a day | |
if [ "$AGE" = "0" ] | |
then | |
AGE_PATTERN="${AGE_PATTERN}|." | |
fi | |
echo "CLEAN UP JOBS with COMPLETED=$COMPLETED; and AGE>=$AGE (AGE PATTERN $AGE_PATTERN); and job NAME PATTERN $NAME_PATTERN" | |
JOB_LIST=$(kubectl get jobs --sort-by=.metadata.creationTimestamp | awk -v completed="$COMPLETED" '$2 ~ completed' | awk -v pattern="$AGE_PATTERN" '$4 ~ pattern' | awk -v pattern="$NAME_PATTERN" '$1 ~ pattern' | awk '{print $1}') | |
else | |
JOB_LIST=$(cat $BY_LIST_FILE) | |
fi | |
l=1 | |
size=128 | |
TOTAL=$(echo $JOB_LIST | wc -w) | |
echo ">>>>>> To delete $TOTAL jobs in total" | |
while (( $(echo "$l <= $TOTAL" | bc -l) )) | |
do | |
le=$(echo "$l + $size" | bc -l) | |
echo ">>>>>> Fetching job $l to $le (size $size ) of $TOTAL" | |
#list jobs to delete | |
echo $JOB_LIST | cut -d' ' -f${l}-${le} | |
#delete jobs | |
kubectl delete --cascade=true --timeout=6s job $( echo $JOB_LIST | cut -d' ' -f${l}-${le} ) | |
l=$(echo "$le + 1" | bc -l) | |
done |
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