Codility BinaryGap - Python solution

BinaryGap.py

def solution(N):
    # write your code in Python 3.6
    meet_one = False
    count = 0
    keep = []
    while N:
        if meet_one and N & 1 == 0:
            count+=1
        
        if  N & 1:
            meet_one = True
            keep.append(count)
            count = 0
        N >>=1

    return max(keep)