Created
September 29, 2012 13:09
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leetcode Search Insert Position
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/* | |
Given a sorted array and a target value, return the index if the target is found. | |
If not, return the index where it would be if it were inserted in order. | |
You may assume no duplicates in the array. | |
Here are few examples. | |
[1,3,5,6], 5 → 2 | |
[1,3,5,6], 2 → 1 | |
[1,3,5,6], 7 → 4 | |
[1,3,5,6], 0 → 0 | |
*/ | |
class Solution { | |
public: | |
int searchInsert(int A[], int n, int target) { | |
if(n < 1) { | |
return 0; | |
} | |
int low = 0; | |
int high = n-1; | |
int mid; | |
int pos; | |
while(low <= high) { | |
mid = low + (high-low)/2; | |
if(A[mid] == target) { | |
return mid; | |
} else if(A[mid] > target) { | |
high = mid - 1; | |
pos = mid; | |
} else { | |
low = mid + 1; | |
pos = mid + 1; | |
} | |
} | |
return pos; | |
} | |
}; |
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