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@hyfrey
Created October 1, 2012 12:00
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leetcode Symmetric Tree
/*
Symmetric Tree
Given a binary tree, check whether it is a mirror of itself
(ie, symmetric around its center).
For example, this binary tree is symmetric:
1
/ \
2 2
/ \ / \
3 4 4 3
But the following is not:
1
/ \
2 2
\ \
3 3
Note:
Bonus points if you could solve it both recursively and iteratively.
*/
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isSymmetric(TreeNode *left, TreeNode *right) {
if(left == NULL && right == NULL) {
return true;
} else if(left == NULL || right == NULL) {
return false;
}
return left->val == right->val &&
isSymmetric(left->right, right->left) &&
isSymmetric(left->left, right->right);
}
bool isSymmetric(TreeNode *root) {
if(root == NULL) {
return true;
}
return isSymmetric(root->left, root->right);
}
};
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