Created
October 18, 2012 08:40
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leetcode Unique Binary Search Trees II
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/* | |
Given n, generate all structurally unique BST's (binary search trees) that | |
store values 1...n. | |
For example, | |
Given n = 3, your program should return all 5 unique BST's shown below. | |
1 3 3 2 1 | |
\ / / / \ \ | |
3 2 1 1 3 2 | |
/ / \ \ | |
2 1 2 3 | |
*/ | |
/** | |
* Definition for binary tree | |
* struct TreeNode { | |
* int val; | |
* TreeNode *left; | |
* TreeNode *right; | |
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
public: | |
void generate(vector<TreeNode *> &ret, int left, int right) { | |
if(left > right) { | |
ret.push_back(NULL); | |
return; | |
} | |
for(int i = left; i <= right; i++) { | |
vector<TreeNode *> lefts; | |
generate(lefts, left, i-1); | |
vector<TreeNode *> rights; | |
generate(rights, i+1, right); | |
for(int u = 0; u < lefts.size(); u++) { | |
for(int v = 0; v < rights.size(); v++) { | |
TreeNode *root = new TreeNode(i); | |
root->left = lefts[u]; | |
root->right = rights[v]; | |
ret.push_back(root); | |
} | |
} | |
} | |
} | |
vector<TreeNode *> generateTrees(int n) { | |
vector<TreeNode *> ret; | |
generate(ret, 1, n); | |
return ret; | |
} | |
}; |
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