q.c

#include <stdio.h>
#include <stdlib.h>

int main() {
	// your code goes here
	char *s1, *s2;
	printf("%d%d", sizeof(s1), sizeof(s2));
	return 0;
}

// codechef IDE gives answer - 4,4
// my machine gives - 8,8
// correct answer - 4,2

q1.9.c

# include <stdio.h>
# include <stdlib.h>


int main()
{
	extern int i;
    printf("\n%d",i);
     return 0;
 }
int i=20;

// how come this works?

q2-1.c

# include <stdio.h>

int main()
{

	int i=4;

	switch(i)
	{

		default:
			printf("\ndefault\n");

		case 1:
			printf("\ncase 1\n");
			break;

		case 2:
			printf("\ncase 2\n");
			break;

		case 3:
			printf("\ncase 3\n");
			break;

	}

	return 0;

}

/* gives output -
default

case 1

how?
*/

q3-5.c

# include <stdio.h>

int main()
{

	int x=10,y=20,z=5,i;
	i = x<y<z;
	printf("\n%d",i);
	return 0;

}

// how does this gives answer 1?

test.c

#include <stdio.h>

int main() {

	int arr[] = {2,3,4, 1,6};

	printf("\n%d\n%d", arr, sizeof ( arr ));
	return 0;
}


//output - 123445, 20
// books gives 10

• how would you dynamically allocate a 1D array?
• how would you dynamically allocate a 2D array?