Created
November 5, 2020 14:50
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[2018 카카오 공채] 뉴스 클러스터링
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| import java.util.LinkedList; | |
| import java.util.List; | |
| import java.util.regex.Pattern; | |
| import java.util.stream.Collectors; | |
| import java.util.stream.IntStream; | |
| // https://programmers.co.kr/learn/courses/30/lessons/17677 | |
| class Solution { | |
| public int solution(String str1, String str2) { | |
| List<String> s1 = split2(str1); | |
| List<String> s2 = split2(str2); | |
| int n1 = intersectCount(s1, s2); | |
| int n2 = unionCount(s1, s2); | |
| if (n1 == 0 && n2 == 0) return 65536; | |
| return n1 * 65536 / n2; | |
| } | |
| public List<String> split2(String str) { | |
| return IntStream.range(0, str.length() - 1) | |
| .mapToObj(i -> str.substring(i, i + 2)) | |
| .map(String::toUpperCase) | |
| .filter(s -> Pattern.matches("[A-Z]+", s)) | |
| .collect(Collectors.toList()); | |
| } | |
| public int intersectCount(List<String> s1, List<String> s2) { | |
| List<String> ss2 = new LinkedList<>(s2); | |
| int count = 0; | |
| for (String s : s1) { | |
| if (ss2.remove(s)) count += 1; | |
| } | |
| return count; | |
| } | |
| public int unionCount(List<String> s1, List<String> s2) { | |
| List<String> ss2 = new LinkedList<>(s2); | |
| int count = 0; | |
| for (String s : s1) { | |
| ss2.remove(s); | |
| count += 1; | |
| } | |
| return count + ss2.size(); | |
| } | |
| } |
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