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October 15, 2013 18:58
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[18:25] <ibanezmatt13_> internet failed | |
[18:26] <eroomde> np | |
[18:26] <ibanezmatt13_> so yeah, I've tried a few methods and keep getting lost somewhere | |
[18:26] <ibanezmatt13_> I tried to replace multiple resistors with 1 resistor to narrow it down | |
[18:27] <eroomde> it's ok, you're doing what everyone does | |
[18:27] <eroomde> draws a net | |
[18:27] <ibanezmatt13_> yes | |
[18:27] <eroomde> but then reaslises that won't work because two end edges of the net are actually electrically connected | |
[18:27] <eroomde> and wonders how you're meant to deal with things folding back on themselves | |
[18:28] <eroomde> nd so on | |
[18:28] <ibanezmatt13_> yep | |
[18:28] <eroomde> and you'll fill 20 sheets of paper with lots of 1/R crap that isn't getting you an answer | |
[18:28] <ibanezmatt13_> 3 pages so far | |
[18:28] <eroomde> ok | |
[18:28] <eroomde> let's consider ohm's law | |
[18:28] <eroomde> because it's really powerful | |
[18:28] <ibanezmatt13_> ok | |
[18:29] <eroomde> say i have two points on a circuit, some random steady-state circuit | |
[18:29] <eroomde> they're both at the same voltage | |
[18:29] <ibanezmatt13_> ok | |
[18:29] <eroomde> i dunno what this circuit is, say some christmas lights or something | |
[18:29] <eroomde> doesn't matter | |
[18:29] <eroomde> you measure the voltage at point a, it's, say, 3V | |
[18:30] <eroomde> you measure the voltage at point b somewhere else in the circuit, it's at 3V too | |
[18:30] <eroomde> what would happen if i connected those two points with a wire? | |
[18:30] <ibanezmatt13_> 0V? | |
[18:30] <ibanezmatt13_> no | |
[18:30] <ibanezmatt13_> erm | |
[18:30] <eroomde> explain | |
[18:31] <eroomde> don't 'think' so much as use ohms law to tell me exactly | |
[18:31] <ibanezmatt13_> well I was going to say there's no overall potential | |
[18:31] <ibanezmatt13_> don't know | |
[18:31] <eroomde> by 'think' i mean, go on intuition | |
[18:31] <eroomde> ok, that's a very good start | |
[18:32] <eroomde> though you should be strict with your terminology and say there's no potential *difference* | |
[18:32] <eroomde> which is what we define 'voltage' to be | |
[18:32] <ibanezmatt13_> ok | |
[18:32] <eroomde> potential difference is the better term for voltage really | |
[18:32] <eroomde> ok, so there's no potential difference between these two points | |
[18:32] <eroomde> so what happens if i connect them with a wire? | |
[18:33] <ibanezmatt13_> err | |
[18:33] <ibanezmatt13_> nothin | |
[18:33] <eroomde> why? | |
[18:33] <eroomde> explain your reasoning with reference to ohm's law | |
[18:34] <ibanezmatt13_> I can't think how to refer to ohm's law | |
[18:34] <ibanezmatt13_> like use an equation? | |
[18:34] <eroomde> yes | |
[18:34] <eroomde> always yes :) | |
[18:34] <ibanezmatt13_> ah | |
[18:34] <ibanezmatt13_> erm | |
[18:34] <eroomde> equations are fantastic | |
[18:34] <eroomde> you can prove what you're saying with them | |
[18:34] <ibanezmatt13_> ok so | |
[18:35] <ibanezmatt13_> pd = 0, so IR = 0. Erm, either current or resistance is 0.] | |
[18:35] <ibanezmatt13_> I don't know | |
[18:35] <eroomde> yes exactly! | |
[18:35] <eroomde> now, you know r is never 0 exactly | |
[18:35] <ibanezmatt13_> no | |
[18:35] <eroomde> so it must be that I is zero | |
[18:35] <ibanezmatt13_> oh cool | |
[18:35] <eroomde> you can disambiguate that by rearranging | |
[18:35] <eroomde> I = V/R | |
[18:36] <eroomde> V= 0 there I = 0 | |
[18:36] <eroomde> therefore* | |
[18:36] <ibanezmatt13_> of course | |
[18:36] <eroomde> cool | |
[18:36] <ibanezmatt13_> interview questions? seriously? :) | |
[18:36] <eroomde> so, a circuit only does things when there's a flow of current | |
[18:36] <eroomde> that's what a circuit is | |
[18:36] <ibanezmatt13_> of course | |
[18:36] <eroomde> no, the resistor cube is the interview question | |
[18:36] <ibanezmatt13_> right | |
[18:37] <eroomde> i'm just steering you to the aha moment you need to answer this q | |
[18:37] <ibanezmatt13_> right, so I should be able to figure this now | |
[18:37] <eroomde> so, summarise for me, if we connect two pooints on a circuit at the same potential, does it affect the circuit? | |
[18:37] <ibanezmatt13_> no | |
[18:37] <eroomde> perfect | |
[18:38] <eroomde> ok, so now go and tell me the resistence across the cube | |
[18:38] <ibanezmatt13_> erm | |
[18:40] <ibanezmatt13_> So I'm working out total R? | |
[18:40] <eroomde> the R you see from one corner of the cube to the opposite corner | |
[18:41] <ibanezmatt13_> Assuming what? | |
[18:41] <eroomde> if you were to put a multimeter across | |
[18:41] <eroomde> where each edge of the cube is a 1ohm resistor | |
[18:41] <eroomde> http://www.rfcafe.com/references/electrical/images/resistor-cube-kirt-1.gif | |
[18:41] <eroomde> R between A and B | |
[18:42] <ibanezmatt13_> I'm now thinking of how a multimeter actually works, must being straying off topic | |
[18:42] <eroomde> yep | |
[18:43] <eroomde> but it works by injecting a known constant current and measuring the voltage between A and B | |
[18:43] <ibanezmatt13_> oh right, that may help | |
[18:43] <eroomde> no not really | |
[18:43] <ibanezmatt13_> oh | |
[18:43] <eroomde> you don't need to know how it works | |
[18:43] <eroomde> it just measures the resistence between A and B | |
[18:43] <eroomde> we want to know what that resitence is | |
[18:44] <ibanezmatt13_> they have the same PD | |
[18:44] <eroomde> thing about the discussion we just had. the clue to analysing this circuit is there | |
[18:44] <ibanezmatt13_> at each point? | |
[18:44] <eroomde> which points have the same PD? | |
[18:44] <ibanezmatt13_> one corner to other | |
[18:44] <ibanezmatt13_> diagonal | |
[18:44] <eroomde> nope | |
[18:44] <ibanezmatt13_> oh | |
[18:45] <eroomde> if i were to put a battery between A and B, it wouldn't be a short circuit | |
[18:45] <eroomde> so, nope | |
[18:45] <eroomde> otherwise if A and B did have the same PD, then you could just replace that whole resistor cube with a wire | |
[18:45] <eroomde> i.e. a short | |
[18:45] <ibanezmatt13_> ah yes | |
[18:45] <eroomde> and that clearly isn't the same thing | |
[18:45] <ibanezmatt13_> of course | |
[18:46] <eroomde> but keep wondering about which points on that cube are at the same potential | |
[18:46] <ibanezmatt13_> ok | |
[18:46] <ibanezmatt13_> none of them | |
[18:47] <ibanezmatt13_> wait | |
[18:47] <eroomde> imagine you stick that battery across A and B | |
[18:47] <eroomde> ok, waiting | |
[18:47] <ibanezmatt13_> same pd across each resistor? | |
[18:47] <ibanezmatt13_> as they're identical | |
[18:48] <eroomde> not necessarily no | |
[18:48] <ibanezmatt13_> oh | |
[18:48] <eroomde> depends on how they're all connected up | |
[18:48] <ibanezmatt13_> oh of course | |
[18:48] <ibanezmatt13_> if in parallel | |
[18:48] <ibanezmatt13_> ok erm | |
[18:48] <eroomde> so imagine this battery we connect to A and B is say 5V | |
[18:48] <ibanezmatt13_> ok | |
[18:49] <eroomde> if you get your voltage meter out and randomly probe around, you know you're gonna see voltages between 5 and 0V | |
[18:49] <eroomde> 5V and A, 0V and B, stuff in between in other bits of the cube | |
[18:49] <ibanezmatt13_> ok | |
[18:49] <eroomde> happy with that? | |
[18:49] <ibanezmatt13_> yep | |
[18:49] <eroomde> right | |
[18:50] <eroomde> so, say you're being systematic about it | |
[18:50] <eroomde> you first probe A, you see 5V | |
[18:50] <eroomde> what would be the next obvious place(s) to probe? | |
[18:50] <ibanezmatt13_> B | |
[18:50] <eroomde> ok, that's 0V | |
[18:50] <eroomde> where next? | |
[18:50] <ibanezmatt13_> All branches connected to B? | |
[18:50] <ibanezmatt13_> no | |
[18:51] <ibanezmatt13_> wait yes | |
[18:51] <ibanezmatt13_> across each resistor connected at B | |
[18:51] <eroomde> ok, so you mean just on the other sides to B of the 3 resistors connected to B? | |
[18:51] <eroomde> ah good :) | |
[18:51] <ibanezmatt13_> that's what Imeant | |
[18:51] <eroomde> and what would you expect those 3 voltages to be like, relative to one another? | |
[18:52] <ibanezmatt13_> The same | |
[18:52] <ibanezmatt13_> parallel | |
[18:52] <eroomde> given the cube is nicely symmetrical | |
[18:52] <eroomde> yes! | |
[18:52] <eroomde> so you could connect up those points with your virtual bit of wire | |
[18:52] <eroomde> and not have the circuit be affected | |
[18:52] <ibanezmatt13_> which points? | |
[18:52] <ibanezmatt13_> the three points | |
[18:53] <eroomde> you tell me | |
[18:53] <ibanezmatt13_> yes | |
[18:53] <ibanezmatt13_> the three points | |
[18:53] <eroomde> yes | |
[18:53] <ibanezmatt13_> ok | |
[18:53] <eroomde> so you now have 3 resistors connected to each other at both ends | |
[18:53] <eroomde> i.e., in parallel | |
[18:54] <ibanezmatt13_> yes | |
[18:54] <eroomde> great | |
[18:54] <eroomde> now spot the symetrry | |
[18:54] <eroomde> of the cube | |
[18:54] <ibanezmatt13_> diagonal line | |
[18:54] <ibanezmatt13_> through | |
[18:54] <eroomde> and go away for a bit to work out the resistence between A and B | |
[18:57] <ibanezmatt13_> It doesn't seem to be clicking | |
[18:58] <eroomde> try and draw it 2d | |
[18:58] <ibanezmatt13_> the cube net? | |
[18:58] <eroomde> you've started well by saying the first 3 resistros can be connected in parallel | |
[18:58] <eroomde> not the cube net | |
[18:58] <eroomde> the circuit | |
[18:59] <ibanezmatt13_> oh | |
[18:59] <ibanezmatt13_> ok | |
[18:59] <eroomde> using your insight about how you can put in virtual wires | |
[19:00] <ibanezmatt13_> they're all in parallel | |
[19:01] <eroomde> no | |
[19:01] <ibanezmatt13_> oh | |
[19:01] <ibanezmatt13_> oh of course | |
[19:01] <ibanezmatt13_> sorry | |
[19:04] <eroomde> where are you at? | |
[19:04] <ibanezmatt13_> a very strange diagram that looks kinda good | |
[19:04] <ibanezmatt13_> let me take a picture | |
[19:04] <ibanezmatt13_> one sec | |
[19:06] <ibanezmatt13_> http://sdrv.ms/19Fat79 | |
[19:06] <ibanezmatt13_> three parallel resistors in the middle | |
[19:06] <ibanezmatt13_> and each ones connects to a further two in parallel | |
[19:06] <ibanezmatt13_> only 9 there though | |
[19:07] <eroomde> where the the 3 in parallel? | |
[19:07] <ibanezmatt13_> right in the middle | |
[19:07] <eroomde> they don't look in parallel to me | |
[19:07] <eroomde> you haven't connected the other ends together | |
[19:07] <ibanezmatt13_> oh | |
[19:07] <ibanezmatt13_> ah yes | |
[19:08] <ibanezmatt13_> damn | |
[19:08] <eroomde> remember, these virtual wires are your friends | |
[19:08] <eroomde> draw them | |
[19:08] <ibanezmatt13_> I've not got to that part :/ | |
[19:08] <ibanezmatt13_> oh waity | |
[19:08] <ibanezmatt13_> think I get what you mean by virtual wires | |
[19:08] <eroomde> make them real wires | |
[19:08] <eroomde> imagine soldering them in there | |
[19:09] <eroomde> then draw *that* circuit | |
[19:09] <ibanezmatt13_> across each resistor? | |
[19:09] <ibanezmatt13_> the wires | |
[19:09] <eroomde> just such that you connect up the points you've identified as being at the same potential | |
[19:09] <eroomde> which so far iirc is the first 3 corners on the other side of the 3 resistros from B | |
[19:09] <ibanezmatt13_> yep | |
[19:09] <eroomde> ok | |
[19:10] <eroomde> now when i brough up symmetry, think about how it works for A too | |
[19:10] <ibanezmatt13_> same principle | |
[19:10] <eroomde> yep! | |
[19:10] <ibanezmatt13_> still don't know the answer | |
[19:11] <eroomde> i have drawn something for you | |
[19:11] <ibanezmatt13_> very kind of you | |
[19:11] <eroomde> https://www.dropbox.com/s/qe6irwe5pjfk477/2013-10-15%2019.03.49.jpg | |
[19:11] <ibanezmatt13_> ok so you've labelled the resistors? | |
[19:12] <eroomde> yes, just so you can see what's going on | |
[19:12] <eroomde> so the dotted lines are my virtual wires | |
[19:12] <eroomde> you can see if connected up the 3 points are resistors 1,2,3 | |
[19:13] <eroomde> yep? | |
[19:13] <eroomde> you can see i've* | |
[19:13] <ibanezmatt13_> erm one sec | |
[19:13] <eroomde> after resistors* | |
[19:13] <eroomde> sorry can't type | |
[19:13] <ibanezmatt13_> ok yes | |
[19:13] <eroomde> and i've done the same with dotted lines for the symmetrical case for B | |
[19:13] <eroomde> 10,11,12 | |
[19:14] <ibanezmatt13_> those dotted lines appear to be connecting 10,11 | |
[19:14] <ibanezmatt13_> sorry | |
[19:14] <ibanezmatt13_> 10,12 | |
[19:14] <eroomde> oh sorry | |
[19:14] <eroomde> crap diagram | |
[19:14] <ibanezmatt13_> 11 to me looks out of the question | |
[19:15] <eroomde> well, the nodes are 10,11, and 12 are all connected | |
[19:15] <eroomde> with dotted lines | |
[19:15] <ibanezmatt13_> oh I see | |
[19:15] <ibanezmatt13_> I was visualising it wrong | |
[19:16] <eroomde> cool | |
[19:16] <eroomde> should have used colour | |
[19:16] <ibanezmatt13_> I still can't see the point of the wires yet :/ | |
[19:16] <eroomde> look at the diagram on the right! | |
[19:16] <eroomde> let's start from A | |
[19:17] <ibanezmatt13_> ok | |
[19:17] <eroomde> A is connected to resistors 1,2 and 3 | |
[19:17] <ibanezmatt13_> yes | |
[19:17] <eroomde> we have agreed that the other sides of 1,2 and 3 can all be connected together | |
[19:17] <eroomde> because that won't affect the circuit | |
[19:17] <eroomde> yep? | |
[19:17] <ibanezmatt13_> yes, same pd | |
[19:17] <eroomde> yep | |
[19:17] <eroomde> ok, so i draw the first bit of the diagram on the right | |
[19:18] <eroomde> 1,2 and 3 in parallel | |
[19:18] <ibanezmatt13_> yes | |
[19:18] <eroomde> they're basically all the same point now | |
[19:18] <eroomde> a single node | |
[19:18] <ibanezmatt13_> ok | |
[19:18] <eroomde> even though it's actually 3 nodes, you can model it as a single virtual node | |
[19:18] <eroomde> because we've connected all the nodes up with wires | |
[19:18] <eroomde> so | |
[19:18] <eroomde> that's the first bit | |
[19:18] <ibanezmatt13_> ok | |
[19:19] <eroomde> now we do the same with the bottom 3 starting from B | |
[19:19] <eroomde> for 10,11 and 12 | |
[19:19] <ibanezmatt13_> ok | |
[19:19] <eroomde> and i draw them in parallel at the bottom of the diagram on the right | |
[19:19] <eroomde> happy? | |
[19:19] <eroomde> so far... | |
[19:19] <ibanezmatt13_> I think so yeah | |
[19:19] <eroomde> so now we have to deal with all the crap in the middle | |
[19:19] <eroomde> 4,5,6,7,8,9 | |
[19:20] <eroomde> now, look at any of those resistors you like | |
[19:20] <eroomde> they go from the virtual node on the A side to the virtual node on the B side, i.e. from a point connected by the dotted lines on the A side to a point connected to the dotted lines on the B side | |
[19:20] <ibanezmatt13_> ok | |
[19:20] <eroomde> do you see that? | |
[19:20] <eroomde> from the left hand diagram | |
[19:21] <ibanezmatt13_> let me have a look | |
[19:21] <ibanezmatt13_> ah yes :) | |
[19:21] <ibanezmatt13_> cool | |
[19:21] <eroomde> so, does the diagram on the right make sense now? | |
[19:22] <ibanezmatt13_> yes but I'd have never thought of that | |
[19:22] <eroomde> welcome to interview questions :D | |
[19:22] <eroomde> don't worry, it seems terrifying now | |
[19:22] <ibanezmatt13_> I'm gonna become a binman | |
[19:22] <eroomde> but with practice you start to see how to think about problems better | |
[19:22] <eroomde> lol | |
[19:22] <ibanezmatt13_> still not got the total R | |
[19:22] <eroomde> i nearly cried when i first saw a cambridge exam question in first year | |
[19:23] <ibanezmatt13_> not surpirsed | |
[19:23] <eroomde> well, it's 3 in parallel + 6 in parallel + 3 in parallel | |
[19:23] <eroomde> so 1/3 + 1/6 + 1/3 | |
[19:23] <ibanezmatt13_> Total R = 6/5 | |
[19:24] <eroomde> 5/6 | |
[19:24] <eroomde> 2/6+1/6+2/6 | |
[19:24] <ibanezmatt13_> is that not the reciprocal? | |
[19:24] <ibanezmatt13_> ie 1/Rtotal | |
[19:24] <eroomde> so the first bit is 1/Rtot | |
[19:24] <eroomde> where rtot = 3 | |
[19:24] <eroomde> so the first bit is 1/3 | |
[19:25] <eroomde> it's connected *in series* with the second bit and third bit | |
[19:25] <ibanezmatt13_> oh | |
[19:25] <ibanezmatt13_> I see | |
[19:25] <ibanezmatt13_> total r = 5/6 | |
[19:25] <eroomde> so you have 3 chunks connected in series | |
[19:25] <eroomde> and within each chunk, they connected in parallel | |
[19:26] <ibanezmatt13_> well, it all makes sense now I guess. But it wouldn't have got me through the interview! | |
[19:26] <eroomde> we'll keep practicing random things like that | |
[19:26] <eroomde> it's 100% practice | |
[19:27] <eroomde> you'll find you start being able to solve them more easily | |
[19:27] <ibanezmatt13_> I need to do more of these things | |
[19:27] <ibanezmatt13_> Can we do one every night? | |
[19:27] <eroomde> but they're a definite step up from a-level, were it's more knowing how to crank the machine rather than have some insight | |
[19:27] <eroomde> i'm probably a bit busy for that, but can certainly do them every now and then | |
[19:27] <ibanezmatt13_> fair enough. Thanks for the help | |
[19:29] <ibanezmatt13_> This exercise has made me a little more doubtful about whether I'll be able to get half decent grades. :/ | |
[19:29] <eroomde> almost no one can answer that question in the interviews | |
[19:29] <eroomde> don't worry | |
[19:30] <ibanezmatt13_> I got an email from a teacher who reviewed my dislexia test. I'm not dislexic apparently, but he said that the test has suggested I will find the majority of my maths course very difficult and that I need to speak to him about it. Bloody marvellous | |
[19:30] <eroomde> that's vastly harder than anything a-levels would ask of you | |
[19:31] <eroomde> it's just practice. thinking mathematically is a muscle | |
[19:31] <ibanezmatt13_> mm | |
[19:32] <eroomde> i promise | |
[19:32] <eroomde> in october of first year i tried my first exam question | |
[19:32] <eroomde> and had a moment like you just had | |
[19:32] <eroomde> thinking this is so so so so far beyond my powers of thinking | |
[19:32] <eroomde> and by the summer i could actually do them | |
[19:32] <eroomde> don't worry about it, we'll just practice | |
[19:33] <ibanezmatt13_> see, I'm not actually that intelligent. I just have a very good work ethi | |
[19:33] <ibanezmatt13_> c | |
[19:33] <eroomde> everyone who did well at cam said the same thing | |
[19:33] <eroomde> it's totally about consistently plugging away | |
[19:33] <eroomde> nothing is difficult, it just takes consistent effort ot chip away at it | |
[19:33] <eroomde> to understand it | |
[19:34] <ibanezmatt13_> I guess I'll just plod on and see what happens | |
[19:34] <eroomde> that's all you can do | |
[19:35] <eroomde> and the right thing to do | |
[19:35] <ibanezmatt13_> Thankfully, my GCSE results mean I have safely got a place as a bus driver or local class 140 train driver at a push | |
[19:35] <eroomde> nice to have a backup! | |
[19:35] <ibanezmatt13_> :) | |
[19:36] <ibanezmatt13_> You never know, NORB might go global and I'll become Richard Branson of NORB technologies | |
[19:39] <ibanezmatt13_> eroomde, do you know of any other puzzles like that resistor one that I can look at? | |
[19:40] <eroomde> nope, wouldn't worry about it though | |
[19:40] <ibanezmatt13_> ok | |
[19:49] <eroomde> right, off home | |
[19:49] <eroomde> bbl |
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