Created
February 25, 2021 04:00
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`std::vector<T&>`; because, why not?
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#include <iostream> | |
#include <vector> | |
namespace std { | |
template<class T> | |
class vector<T&> { | |
public: | |
vector() : data(new T*[capacity]) {} | |
size_t size() const { | |
return d_size; | |
} | |
void push_back(T& x) { | |
if (d_size == capacity) { | |
capacity <<= 1; | |
T** old_data = data; | |
data = new T*[capacity]; | |
for (size_t i = 0; i < d_size; ++i) | |
data[i] = old_data[i]; | |
delete [] old_data; | |
} | |
data[d_size] = &x; | |
++d_size; | |
} | |
T& operator[](size_t i) { | |
return *data[i]; | |
} | |
const T& operator[](size_t i) const { | |
return *data[i]; | |
} | |
~vector() { | |
delete [] data; | |
} | |
private: | |
size_t d_size = 0; | |
size_t capacity = 2; | |
T** data; | |
}; | |
} | |
int main() | |
{ | |
std::vector<int&> v; | |
int a = 10; | |
for (auto i = 0; i < 10000; ++i) | |
v.push_back(a); | |
v[10] = 100; | |
std::cout << v.size() << '\n'; | |
std::cout << v[0] << '\n'; | |
return 0; | |
} |
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