#哈希表 #有效的字母异位词

valid-anagram.cpp

class Solution {
public:
    bool isAnagram(string s, string t) {
        if (s.size() != t.size()) return false;

        int table[26] = {0};
        for (int i = 0; i < s.size(); ++i) {
            table[s[i] - 'a']++;
            table[t[i] - 'a']--;
        }
        for (int i = 0; i < 26; ++i) {
            if (table[i] != 0)
                return false;
        }
        return true;
    }
};